Myujth

taskList.push(
 const data = 
 url: 'http://$requestUrl?$argsString',
 headers: 
 'Content-Type': 'application/octet-stream',
 Authorization: signature //,
 //'Content-Length': buffer.length
 ,
 method: 'POST',
 data: buffer
 
 return axios(data)
 )

try 
 const data = await Promise.all(taskList)
 const res = data.map(d => d.data)
 console.log(res)
 //ctx.state.data = res
 catch (e) 
 console.log(e)
 throw e
 

How to do not wait all requests finish, because all finish needs too long time. If any request finish, I print it out, it will be very fast for users.

To run each Promise just add a .then() to each of one them or to the Promise.all, however you will not be able to .map the data after:

try {
 const data = Promise.all(taskList).then(() => console.log('finished'));
 // this will not wait to run, so data will be probably undefined
 const res = data.map(d => d.data)
 ...

So I'd suggest following the pattern and waiting for them to finish.

If it's taking too long maybe you should try improve the performance of the response in the back-end if that's possible.

In case each response should be logged as soon as it's completed, it should be:

const responses = await Promise.all(taskList.map(async task => 
 const data = await task;
 console.log(data);
 return data;
));