not able to sort textfile input line by line in an output file
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I ran into a problem. I have written following program to sort string of integers in a text file and output the sorted list of integers in an output file. The input file can contain multiple lines of integers and I want to sort them one line at a time and print it out in my output file.
The problem is program reads all the lines from input text and prints out a continuous line of sorted numbers in the output file. How do I make program sort and print sorted list line by line in output file ?
import java.util.*;
import java.io.File;
import java.io.FileNotFoundException;
import java.io.FileReader;
import java.io.FileWriter;
import java.io.IOException;
import java.io.PrintWriter;
import java.util.Scanner;
public class MergeSort
up vote
1
down vote
favorite
I ran into a problem. I have written following program to sort string of integers in a text file and output the sorted list of integers in an output file. The input file can contain multiple lines of integers and I want to sort them one line at a time and print it out in my output file.
The problem is program reads all the lines from input text and prints out a continuous line of sorted numbers in the output file. How do I make program sort and print sorted list line by line in output file ?
import java.util.*;
import java.io.File;
import java.io.FileNotFoundException;
import java.io.FileReader;
import java.io.FileWriter;
import java.io.IOException;
import java.io.PrintWriter;
import java.util.Scanner;
public class MergeSort improve this answer
answered Nov 11 at 1:28
muradm
717419
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outFile.close();
answered Nov 11 at 1:28
muradm
717419
You are missing println. Snippet:
for (int i = 0; i <= intarray.length - 1; i++)
outFile.print(intarray[i] + " ");
outFile.println(); // this is missing
}
outFile.close();
answered Nov 11 at 1:28
muradm
717419
answered Nov 11 at 1:28
muradm
717419
answered Nov 11 at 1:28
muradm
717419
answered Nov 11 at 1:28
muradm
717419
717419
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