TCP Retransmission requests from IPTV Server and TCP Dup Ack Requests from Client
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Server address ( 208.240.190.100) and client ( 210.220.160.48). We are having some problem in the IPTV traffic. It stuck sometimes
and sometimes there is a delay in video . Below mentioned is the tcp dump which i took at server side . In this , we can see that there are lots of TCP re transmission requests coming from Server and Client is sending TCP Duplication Acknowledgement request. Can someone please take a look at the below mentioned packet capture and let me know whether the problem is at the client side or on the server ? as why server is re transmitting the packets .
I did a continuous ping from client to server but could not see any delay or time out.
234 0.672953 210.220.160.48 ------------- 208.240.190.100 TCP 60 51977 → 80 [ACK] Seq=231 Ack=97409 Win=64240 Len=0
235 0.672958 208.240.190.100 ------------ 210.220.160.48 TCP 2974 80 → 51977 [ACK] Seq=114929 Ack=231 Win=41808 Len=2920 [TCP segment of a reassembled PDU]
236 0.679994 210.220.160.48 ------------- 208.240.190.100 TCP 60 [TCP Dup ACK 231#2] 33042 → 80 [ACK] Seq=1 Ack=94901 Win=64240 Len=0
237 0.679998 208.240.190.100 ------------- 210.220.160.48 HTTP 1514 Continuation
238 0.689851 210.220.160.48 -------------- 208.240.190.100 TCP 60 [TCP Dup ACK 231#3] 33042 → 80 [ACK] Seq=1 Ack=94901 Win=64240 Len=0
239 0.689855 208.240.190.100 ------------- 210.220.160.48 HTTP 1514 [TCP Fast Retransmission] Continuation
240 0.693000 210.220.160.48 -------------- 208.240.190.100 TCP 60 51977 → 80 [ACK] Seq=231 Ack=100329 Win=64240 Len=0
241 0.693004 208.240.190.100-------------- 210.220.160.48 TCP 2974 80 → 51977 [ACK] Seq=117849 Ack=231 Win=41808 Len=2920 [TCP segment of a reassembled PDU]
242 0.699995 210.220.160.48 -------------- 208.240.190.100 TCP 60 [TCP Dup ACK 231#4] 33042 → 80 [ACK] Seq=1 Ack=94901 Win=64240 Len=0
Server is also showing some malformed packets in errors of wireshark . Below mentioned are the errors on server side wireshark capture .
1884 TCP: [TCP Fast Retransmission] 80 → 51977 [ACK] Seq=1053709 Ack=231 Win=41808 Len=1460[Reassembly error, protocol TCP: New fragment overlaps old data (retransmission?)]
2335 TCP: [TCP Fast Retransmission] 80 → 51977 [ACK] Seq=1308554 Ack=461 Win=41808 Len=1460[Reassembly error, protocol TCP: New fragment overlaps old data (retransmission?)]
Please help me regarding it that how i can resolve this issue ?
Thanks
tcp tcpdump
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up vote
-2
down vote
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Server address ( 208.240.190.100) and client ( 210.220.160.48). We are having some problem in the IPTV traffic. It stuck sometimes
and sometimes there is a delay in video . Below mentioned is the tcp dump which i took at server side . In this , we can see that there are lots of TCP re transmission requests coming from Server and Client is sending TCP Duplication Acknowledgement request. Can someone please take a look at the below mentioned packet capture and let me know whether the problem is at the client side or on the server ? as why server is re transmitting the packets .
I did a continuous ping from client to server but could not see any delay or time out.
234 0.672953 210.220.160.48 ------------- 208.240.190.100 TCP 60 51977 → 80 [ACK] Seq=231 Ack=97409 Win=64240 Len=0
235 0.672958 208.240.190.100 ------------ 210.220.160.48 TCP 2974 80 → 51977 [ACK] Seq=114929 Ack=231 Win=41808 Len=2920 [TCP segment of a reassembled PDU]
236 0.679994 210.220.160.48 ------------- 208.240.190.100 TCP 60 [TCP Dup ACK 231#2] 33042 → 80 [ACK] Seq=1 Ack=94901 Win=64240 Len=0
237 0.679998 208.240.190.100 ------------- 210.220.160.48 HTTP 1514 Continuation
238 0.689851 210.220.160.48 -------------- 208.240.190.100 TCP 60 [TCP Dup ACK 231#3] 33042 → 80 [ACK] Seq=1 Ack=94901 Win=64240 Len=0
239 0.689855 208.240.190.100 ------------- 210.220.160.48 HTTP 1514 [TCP Fast Retransmission] Continuation
240 0.693000 210.220.160.48 -------------- 208.240.190.100 TCP 60 51977 → 80 [ACK] Seq=231 Ack=100329 Win=64240 Len=0
241 0.693004 208.240.190.100-------------- 210.220.160.48 TCP 2974 80 → 51977 [ACK] Seq=117849 Ack=231 Win=41808 Len=2920 [TCP segment of a reassembled PDU]
242 0.699995 210.220.160.48 -------------- 208.240.190.100 TCP 60 [TCP Dup ACK 231#4] 33042 → 80 [ACK] Seq=1 Ack=94901 Win=64240 Len=0
Server is also showing some malformed packets in errors of wireshark . Below mentioned are the errors on server side wireshark capture .
1884 TCP: [TCP Fast Retransmission] 80 → 51977 [ACK] Seq=1053709 Ack=231 Win=41808 Len=1460[Reassembly error, protocol TCP: New fragment overlaps old data (retransmission?)]
2335 TCP: [TCP Fast Retransmission] 80 → 51977 [ACK] Seq=1308554 Ack=461 Win=41808 Len=1460[Reassembly error, protocol TCP: New fragment overlaps old data (retransmission?)]
Please help me regarding it that how i can resolve this issue ?
Thanks
tcp tcpdump
Doesn't look like a coding question. Try SE.Network Engineering
– Greenonline
Nov 11 at 1:32
add a comment |
up vote
-2
down vote
favorite
up vote
-2
down vote
favorite
Server address ( 208.240.190.100) and client ( 210.220.160.48). We are having some problem in the IPTV traffic. It stuck sometimes
and sometimes there is a delay in video . Below mentioned is the tcp dump which i took at server side . In this , we can see that there are lots of TCP re transmission requests coming from Server and Client is sending TCP Duplication Acknowledgement request. Can someone please take a look at the below mentioned packet capture and let me know whether the problem is at the client side or on the server ? as why server is re transmitting the packets .
I did a continuous ping from client to server but could not see any delay or time out.
234 0.672953 210.220.160.48 ------------- 208.240.190.100 TCP 60 51977 → 80 [ACK] Seq=231 Ack=97409 Win=64240 Len=0
235 0.672958 208.240.190.100 ------------ 210.220.160.48 TCP 2974 80 → 51977 [ACK] Seq=114929 Ack=231 Win=41808 Len=2920 [TCP segment of a reassembled PDU]
236 0.679994 210.220.160.48 ------------- 208.240.190.100 TCP 60 [TCP Dup ACK 231#2] 33042 → 80 [ACK] Seq=1 Ack=94901 Win=64240 Len=0
237 0.679998 208.240.190.100 ------------- 210.220.160.48 HTTP 1514 Continuation
238 0.689851 210.220.160.48 -------------- 208.240.190.100 TCP 60 [TCP Dup ACK 231#3] 33042 → 80 [ACK] Seq=1 Ack=94901 Win=64240 Len=0
239 0.689855 208.240.190.100 ------------- 210.220.160.48 HTTP 1514 [TCP Fast Retransmission] Continuation
240 0.693000 210.220.160.48 -------------- 208.240.190.100 TCP 60 51977 → 80 [ACK] Seq=231 Ack=100329 Win=64240 Len=0
241 0.693004 208.240.190.100-------------- 210.220.160.48 TCP 2974 80 → 51977 [ACK] Seq=117849 Ack=231 Win=41808 Len=2920 [TCP segment of a reassembled PDU]
242 0.699995 210.220.160.48 -------------- 208.240.190.100 TCP 60 [TCP Dup ACK 231#4] 33042 → 80 [ACK] Seq=1 Ack=94901 Win=64240 Len=0
Server is also showing some malformed packets in errors of wireshark . Below mentioned are the errors on server side wireshark capture .
1884 TCP: [TCP Fast Retransmission] 80 → 51977 [ACK] Seq=1053709 Ack=231 Win=41808 Len=1460[Reassembly error, protocol TCP: New fragment overlaps old data (retransmission?)]
2335 TCP: [TCP Fast Retransmission] 80 → 51977 [ACK] Seq=1308554 Ack=461 Win=41808 Len=1460[Reassembly error, protocol TCP: New fragment overlaps old data (retransmission?)]
Please help me regarding it that how i can resolve this issue ?
Thanks
tcp tcpdump
Server address ( 208.240.190.100) and client ( 210.220.160.48). We are having some problem in the IPTV traffic. It stuck sometimes
and sometimes there is a delay in video . Below mentioned is the tcp dump which i took at server side . In this , we can see that there are lots of TCP re transmission requests coming from Server and Client is sending TCP Duplication Acknowledgement request. Can someone please take a look at the below mentioned packet capture and let me know whether the problem is at the client side or on the server ? as why server is re transmitting the packets .
I did a continuous ping from client to server but could not see any delay or time out.
234 0.672953 210.220.160.48 ------------- 208.240.190.100 TCP 60 51977 → 80 [ACK] Seq=231 Ack=97409 Win=64240 Len=0
235 0.672958 208.240.190.100 ------------ 210.220.160.48 TCP 2974 80 → 51977 [ACK] Seq=114929 Ack=231 Win=41808 Len=2920 [TCP segment of a reassembled PDU]
236 0.679994 210.220.160.48 ------------- 208.240.190.100 TCP 60 [TCP Dup ACK 231#2] 33042 → 80 [ACK] Seq=1 Ack=94901 Win=64240 Len=0
237 0.679998 208.240.190.100 ------------- 210.220.160.48 HTTP 1514 Continuation
238 0.689851 210.220.160.48 -------------- 208.240.190.100 TCP 60 [TCP Dup ACK 231#3] 33042 → 80 [ACK] Seq=1 Ack=94901 Win=64240 Len=0
239 0.689855 208.240.190.100 ------------- 210.220.160.48 HTTP 1514 [TCP Fast Retransmission] Continuation
240 0.693000 210.220.160.48 -------------- 208.240.190.100 TCP 60 51977 → 80 [ACK] Seq=231 Ack=100329 Win=64240 Len=0
241 0.693004 208.240.190.100-------------- 210.220.160.48 TCP 2974 80 → 51977 [ACK] Seq=117849 Ack=231 Win=41808 Len=2920 [TCP segment of a reassembled PDU]
242 0.699995 210.220.160.48 -------------- 208.240.190.100 TCP 60 [TCP Dup ACK 231#4] 33042 → 80 [ACK] Seq=1 Ack=94901 Win=64240 Len=0
Server is also showing some malformed packets in errors of wireshark . Below mentioned are the errors on server side wireshark capture .
1884 TCP: [TCP Fast Retransmission] 80 → 51977 [ACK] Seq=1053709 Ack=231 Win=41808 Len=1460[Reassembly error, protocol TCP: New fragment overlaps old data (retransmission?)]
2335 TCP: [TCP Fast Retransmission] 80 → 51977 [ACK] Seq=1308554 Ack=461 Win=41808 Len=1460[Reassembly error, protocol TCP: New fragment overlaps old data (retransmission?)]
Please help me regarding it that how i can resolve this issue ?
Thanks
tcp tcpdump
tcp tcpdump
asked Nov 11 at 1:16
jsnow0445
1
1
Doesn't look like a coding question. Try SE.Network Engineering
– Greenonline
Nov 11 at 1:32
add a comment |
Doesn't look like a coding question. Try SE.Network Engineering
– Greenonline
Nov 11 at 1:32
Doesn't look like a coding question. Try SE.Network Engineering
– Greenonline
Nov 11 at 1:32
Doesn't look like a coding question. Try SE.Network Engineering
– Greenonline
Nov 11 at 1:32
add a comment |
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Doesn't look like a coding question. Try SE.Network Engineering
– Greenonline
Nov 11 at 1:32