Can we restructure destructured parameters in javascript [duplicate]

This question already has an answer here:

Naming destructured argument objects [duplicate]

1 answer

I have destructured my parameters in a function like so:

const obj = a:1 , b:2, c:3, d:4
function1(obj);

function1 (a , b, c ,d) 
 console.log(a);
 console.log(b);

now i need to pass all my params into another function. Is there a way I can acheive something like this?

const obj = a:1 , b:2, c:3, d:4
function1(obj);

function1 (a , b, c ,d) 
 console.log(a);
 console.log(b);
 func2(allMyParams) //instead of func2(a,b,c,d)

edited Nov 12 at 10:52

asked Nov 12 at 10:17

Hassan Naqvi

345

marked as duplicate by Bergi ecmascript-6
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Nov 12 at 11:08

This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.

2

Consider destructuring in the function body?
– evolutionxbox
Nov 12 at 10:23

please add an example of the call of function without name and function1. it is quite unclear if you hand over an array or a single object and what signature do you have for function1.
– Nina Scholz
Nov 12 at 10:25

add a comment |

This question already has an answer here:

Naming destructured argument objects [duplicate]

1 answer

I have destructured my parameters in a function like so:

const obj = a:1 , b:2, c:3, d:4
function1(obj);

function1 (a , b, c ,d) 
 console.log(a);
 console.log(b);

now i need to pass all my params into another function. Is there a way I can acheive something like this?

const obj = a:1 , b:2, c:3, d:4
function1(obj);

function1 (a , b, c ,d) 
 console.log(a);
 console.log(b);
 func2(allMyParams) //instead of func2(a,b,c,d)

edited Nov 12 at 10:52

asked Nov 12 at 10:17

Hassan Naqvi

345

marked as duplicate by Bergi ecmascript-6
Users with the ecmascript-6 badge can single-handedly close ecmascript-6 questions as duplicates and reopen them as needed.

StackExchange.ready(function()
if (StackExchange.options.isMobile) return;

$('.dupe-hammer-message-hover:not(.hover-bound)').each(function()
var $hover = $(this).addClass('hover-bound'),
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$hover.hover(
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$hover.showInfoMessage('',
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dismissable: false,
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Nov 12 at 11:08

This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.

2

Consider destructuring in the function body?
– evolutionxbox
Nov 12 at 10:23

please add an example of the call of function without name and function1. it is quite unclear if you hand over an array or a single object and what signature do you have for function1.
– Nina Scholz
Nov 12 at 10:25

add a comment |

This question already has an answer here:

Naming destructured argument objects [duplicate]

1 answer

I have destructured my parameters in a function like so:

const obj = a:1 , b:2, c:3, d:4
function1(obj);

function1 (a , b, c ,d) 
 console.log(a);
 console.log(b);

now i need to pass all my params into another function. Is there a way I can acheive something like this?

const obj = a:1 , b:2, c:3, d:4
function1(obj);

function1 (a , b, c ,d) 
 console.log(a);
 console.log(b);
 func2(allMyParams) //instead of func2(a,b,c,d)

edited Nov 12 at 10:52

asked Nov 12 at 10:17

Hassan Naqvi

345

This question already has an answer here:

Naming destructured argument objects [duplicate]

1 answer

I have destructured my parameters in a function like so:

const obj = a:1 , b:2, c:3, d:4
function1(obj);

function1 (a , b, c ,d) 
 console.log(a);
 console.log(b);

now i need to pass all my params into another function. Is there a way I can acheive something like this?

const obj = a:1 , b:2, c:3, d:4
function1(obj);

function1 (a , b, c ,d) 
 console.log(a);
 console.log(b);
 func2(allMyParams) //instead of func2(a,b,c,d)

This question already has an answer here:

Naming destructured argument objects [duplicate]

1 answer

javascript ecmascript-6

edited Nov 12 at 10:52

asked Nov 12 at 10:17

Hassan Naqvi

345

edited Nov 12 at 10:52

asked Nov 12 at 10:17

Hassan Naqvi

345

edited Nov 12 at 10:52

asked Nov 12 at 10:17

Hassan Naqvi

345

asked Nov 12 at 10:17

Hassan Naqvi

345

asked Nov 12 at 10:17

Hassan Naqvi

345

marked as duplicate by Bergi ecmascript-6
Users with the ecmascript-6 badge can single-handedly close ecmascript-6 questions as duplicates and reopen them as needed.

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dismissable: false,
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Nov 12 at 11:08

This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.

marked as duplicate by Bergi ecmascript-6
Users with the ecmascript-6 badge can single-handedly close ecmascript-6 questions as duplicates and reopen them as needed.

StackExchange.ready(function()
if (StackExchange.options.isMobile) return;

$('.dupe-hammer-message-hover:not(.hover-bound)').each(function()
var $hover = $(this).addClass('hover-bound'),
$msg = $hover.siblings('.dupe-hammer-message');

$hover.hover(
function()
$hover.showInfoMessage('',
messageElement: $msg.clone().show(),
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);
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Nov 12 at 11:08

This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.

2

Consider destructuring in the function body?
– evolutionxbox
Nov 12 at 10:23

please add an example of the call of function without name and function1. it is quite unclear if you hand over an array or a single object and what signature do you have for function1.
– Nina Scholz
Nov 12 at 10:25

add a comment |

2

Consider destructuring in the function body?
– evolutionxbox
Nov 12 at 10:23

please add an example of the call of function without name and function1. it is quite unclear if you hand over an array or a single object and what signature do you have for function1.
– Nina Scholz
Nov 12 at 10:25

Consider destructuring in the function body?
– evolutionxbox
Nov 12 at 10:23

please add an example of the call of function without name and function1. it is quite unclear if you hand over an array or a single object and what signature do you have for function1.
– Nina Scholz
Nov 12 at 10:25

add a comment |

1 Answer
1

active

oldest

votes

you can use arguments array like object, which contains all passed parameters, since you passed 1 parameter, you can pass it to another function via arguments[0]

function asd (a , b, c ,d) 
 console.log(a);
 console.log(b);
 aa(arguments[0]) 


function aa(a) 
 console.log(a);


asd(a:1,b:2, c:3, d:4);

answered Nov 12 at 10:27

Artyom Amiryan

1,770113

add a comment |

1 Answer
1

active

oldest

votes

1 Answer
1

active

oldest

votes

you can use arguments array like object, which contains all passed parameters, since you passed 1 parameter, you can pass it to another function via arguments[0]

function asd (a , b, c ,d) 
 console.log(a);
 console.log(b);
 aa(arguments[0]) 


function aa(a) 
 console.log(a);


asd(a:1,b:2, c:3, d:4);

answered Nov 12 at 10:27

Artyom Amiryan

1,770113

add a comment |

you can use arguments array like object, which contains all passed parameters, since you passed 1 parameter, you can pass it to another function via arguments[0]

function asd (a , b, c ,d) 
 console.log(a);
 console.log(b);
 aa(arguments[0]) 


function aa(a) 
 console.log(a);


asd(a:1,b:2, c:3, d:4);

answered Nov 12 at 10:27

Artyom Amiryan

1,770113

add a comment |

you can use arguments array like object, which contains all passed parameters, since you passed 1 parameter, you can pass it to another function via arguments[0]

function asd (a , b, c ,d) 
 console.log(a);
 console.log(b);
 aa(arguments[0]) 


function aa(a) 
 console.log(a);


asd(a:1,b:2, c:3, d:4);

answered Nov 12 at 10:27

Artyom Amiryan

1,770113

you can use arguments array like object, which contains all passed parameters, since you passed 1 parameter, you can pass it to another function via arguments[0]

function asd (a , b, c ,d) 
 console.log(a);
 console.log(b);
 aa(arguments[0]) 


function aa(a) 
 console.log(a);


asd(a:1,b:2, c:3, d:4);

function asd (a , b, c ,d) 
 console.log(a);
 console.log(b);
 aa(arguments[0]) 


function aa(a) 
 console.log(a);


asd(a:1,b:2, c:3, d:4);

function asd (a , b, c ,d) 
 console.log(a);
 console.log(b);
 aa(arguments[0]) 


function aa(a) 
 console.log(a);


asd(a:1,b:2, c:3, d:4);

answered Nov 12 at 10:27

Artyom Amiryan

1,770113

answered Nov 12 at 10:27

Artyom Amiryan

1,770113

answered Nov 12 at 10:27

Artyom Amiryan

1,770113

answered Nov 12 at 10:27

Artyom Amiryan

1,770113

add a comment |

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