Possible ways to get the day before the 26 weeks of the current day?
I wish to get the date before the 26 weeks of the current day via C#.
Any one provide me suggestions on the way to get the day?
c# datetime
edited Nov 12 at 12:44
Soner Gönül
79.7k26147271
asked Nov 12 at 12:40
Mahendra Prabhu
2,1171536
add a comment |
I wish to get the date before the 26 weeks of the current day via C#.
Any one provide me suggestions on the way to get the day?
c# datetime
edited Nov 12 at 12:44
Soner Gönül
79.7k26147271
asked Nov 12 at 12:40
Mahendra Prabhu
2,1171536
add a comment |
I wish to get the date before the 26 weeks of the current day via C#.
Any one provide me suggestions on the way to get the day?
c# datetime
edited Nov 12 at 12:44
Soner Gönül
79.7k26147271
asked Nov 12 at 12:40
Mahendra Prabhu
2,1171536
I wish to get the date before the 26 weeks of the current day via C#.
Any one provide me suggestions on the way to get the day?
c# datetime
c# datetime
edited Nov 12 at 12:44
Soner Gönül
79.7k26147271
asked Nov 12 at 12:40
Mahendra Prabhu
2,1171536
edited Nov 12 at 12:44
Soner Gönül
79.7k26147271
asked Nov 12 at 12:40
Mahendra Prabhu
2,1171536
edited Nov 12 at 12:44
Soner Gönül
79.7k26147271
edited Nov 12 at 12:44
Soner Gönül
79.7k26147271
edited Nov 12 at 12:44
Soner Gönül
79.7k26147271
79.7k26147271
asked Nov 12 at 12:40
Mahendra Prabhu
2,1171536
asked Nov 12 at 12:40
Mahendra Prabhu
2,1171536
asked Nov 12 at 12:40
Mahendra Prabhu
2,1171536
2,1171536
add a comment |
add a comment |
3 Answers
3
active
oldest
votes
If I understand you correctly, you could try this:
Since 26 weeks is 26 x 7 days, you can use AddDays on any given DateTime object.
var result = DateTime.Now.AddDays(-26 * 7);
Console.WriteLine(result);
Console.WriteLine(result.DayOfWeek);
Output:
5/14/2018 12:44:36 PM
Monday
See msdn, and note:
The value parameter can be negative or positive.
answered Nov 12 at 12:42
Stefan
8,17873760
add a comment |
Assuming you mean literally 26 weeks of seven days each, you can do it like this:
DateTime.Today.AddDays(-7 * 26)
answered Nov 12 at 12:42
stuartd
49.8k1096123
Thank u for your response. Worked +!
– Mahendra Prabhu
Nov 13 at 4:39
add a comment |
var result = DateTime.Now.AddDays(-26 * 7);
var result2 = DateTime.Now.Add(new TimeSpan(-26 * 7, 0, 0, 0));
var result3 = DateTime.Now.AddHours(-26 * 7 * 24);
var result4 = DateTime.Now.Subtract(new TimeSpan(26 * 7, 0, 0, 0));
var result5 = DateTime.Now.Subtract(new TimeSpan(0, 26 * 7 * 24, 0, 0));
And so one.
answered Nov 12 at 13:00
Nekeniehl
553420
add a comment |
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3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
If I understand you correctly, you could try this:
Since 26 weeks is 26 x 7 days, you can use AddDays on any given DateTime object.
var result = DateTime.Now.AddDays(-26 * 7);
Console.WriteLine(result);
Console.WriteLine(result.DayOfWeek);
Output:
5/14/2018 12:44:36 PM
Monday
See msdn, and note:
The value parameter can be negative or positive.
answered Nov 12 at 12:42
Stefan
8,17873760
add a comment |
If I understand you correctly, you could try this:
Since 26 weeks is 26 x 7 days, you can use AddDays on any given DateTime object.
var result = DateTime.Now.AddDays(-26 * 7);
Console.WriteLine(result);
Console.WriteLine(result.DayOfWeek);
Output:
5/14/2018 12:44:36 PM
Monday
See msdn, and note:
The value parameter can be negative or positive.
answered Nov 12 at 12:42
Stefan
8,17873760
add a comment |
If I understand you correctly, you could try this:
Since 26 weeks is 26 x 7 days, you can use AddDays on any given DateTime object.
var result = DateTime.Now.AddDays(-26 * 7);
Console.WriteLine(result);
Console.WriteLine(result.DayOfWeek);
Output:
5/14/2018 12:44:36 PM
Monday
See msdn, and note:
The value parameter can be negative or positive.
answered Nov 12 at 12:42
Stefan
8,17873760
If I understand you correctly, you could try this:
Since 26 weeks is 26 x 7 days, you can use AddDays on any given DateTime object.
var result = DateTime.Now.AddDays(-26 * 7);
Console.WriteLine(result);
Console.WriteLine(result.DayOfWeek);
Output:
5/14/2018 12:44:36 PM
Monday
See msdn, and note:
The value parameter can be negative or positive.
answered Nov 12 at 12:42
Stefan
8,17873760
edited Nov 12 at 12:58
answered Nov 12 at 12:42
Stefan
8,17873760
answered Nov 12 at 12:42
Stefan
8,17873760
answered Nov 12 at 12:42
Stefan
8,17873760
8,17873760
add a comment |
add a comment |
Assuming you mean literally 26 weeks of seven days each, you can do it like this:
DateTime.Today.AddDays(-7 * 26)
answered Nov 12 at 12:42
stuartd
49.8k1096123
Thank u for your response. Worked +!
– Mahendra Prabhu
Nov 13 at 4:39
add a comment |
Assuming you mean literally 26 weeks of seven days each, you can do it like this:
DateTime.Today.AddDays(-7 * 26)
answered Nov 12 at 12:42
stuartd
49.8k1096123
Thank u for your response. Worked +!
– Mahendra Prabhu
Nov 13 at 4:39
add a comment |
Assuming you mean literally 26 weeks of seven days each, you can do it like this:
DateTime.Today.AddDays(-7 * 26)
answered Nov 12 at 12:42
stuartd
49.8k1096123
Assuming you mean literally 26 weeks of seven days each, you can do it like this:
DateTime.Today.AddDays(-7 * 26)
answered Nov 12 at 12:42
stuartd
49.8k1096123
answered Nov 12 at 12:42
stuartd
49.8k1096123
answered Nov 12 at 12:42
stuartd
49.8k1096123
answered Nov 12 at 12:42
stuartd
49.8k1096123
49.8k1096123
Thank u for your response. Worked +!
– Mahendra Prabhu
Nov 13 at 4:39
add a comment |
Thank u for your response. Worked +!
– Mahendra Prabhu
Nov 13 at 4:39
Thank u for your response. Worked +!
– Mahendra Prabhu
Nov 13 at 4:39
Thank u for your response. Worked +!
– Mahendra Prabhu
Nov 13 at 4:39
add a comment |
var result = DateTime.Now.AddDays(-26 * 7);
var result2 = DateTime.Now.Add(new TimeSpan(-26 * 7, 0, 0, 0));
var result3 = DateTime.Now.AddHours(-26 * 7 * 24);
var result4 = DateTime.Now.Subtract(new TimeSpan(26 * 7, 0, 0, 0));
var result5 = DateTime.Now.Subtract(new TimeSpan(0, 26 * 7 * 24, 0, 0));
And so one.
answered Nov 12 at 13:00
Nekeniehl
553420
add a comment |
var result = DateTime.Now.AddDays(-26 * 7);
var result2 = DateTime.Now.Add(new TimeSpan(-26 * 7, 0, 0, 0));
var result3 = DateTime.Now.AddHours(-26 * 7 * 24);
var result4 = DateTime.Now.Subtract(new TimeSpan(26 * 7, 0, 0, 0));
var result5 = DateTime.Now.Subtract(new TimeSpan(0, 26 * 7 * 24, 0, 0));
And so one.
answered Nov 12 at 13:00
Nekeniehl
553420
add a comment |
var result = DateTime.Now.AddDays(-26 * 7);
var result2 = DateTime.Now.Add(new TimeSpan(-26 * 7, 0, 0, 0));
var result3 = DateTime.Now.AddHours(-26 * 7 * 24);
var result4 = DateTime.Now.Subtract(new TimeSpan(26 * 7, 0, 0, 0));
var result5 = DateTime.Now.Subtract(new TimeSpan(0, 26 * 7 * 24, 0, 0));
And so one.
answered Nov 12 at 13:00
Nekeniehl
553420
var result = DateTime.Now.AddDays(-26 * 7);
var result2 = DateTime.Now.Add(new TimeSpan(-26 * 7, 0, 0, 0));
var result3 = DateTime.Now.AddHours(-26 * 7 * 24);
var result4 = DateTime.Now.Subtract(new TimeSpan(26 * 7, 0, 0, 0));
var result5 = DateTime.Now.Subtract(new TimeSpan(0, 26 * 7 * 24, 0, 0));
And so one.
answered Nov 12 at 13:00
Nekeniehl
553420
answered Nov 12 at 13:00
Nekeniehl
553420
answered Nov 12 at 13:00
Nekeniehl
553420
answered Nov 12 at 13:00
Nekeniehl
553420
553420
add a comment |
add a comment |
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