Low score in Linear Regression with discrete attributes










0














I'm trying to do a linear regression in my dataframe. The dataframe is about apple applications, and I want to predict the notes of applications. The notes are in following format:



1.0
1.5
2.0
2.5
...
5.0


My code is:



atributos = ['size_bytes','price','rating_count_tot','cont_rating','sup_devices_num','num_screenshots','num_lang','vpp_lic']
atrib_prev = ['nota']

X = np.array(data_regress.drop(['nota'],1))
y = np.array(data_regress['nota'])

X = preprocessing.scale(X)

X_train, X_test, y_train, y_test = cross_validation.train_test_split(X, y, test_size=0.2)

clf = LinearRegression()
clf.fit(X_train, y_train)

accuracy = clf.score(X_test, y_test)

print(accuracy)


But my accuracy is 0.046295306696438665. I think this occurs because the linear model is predicting real values, while my 'note' is real, but at intervals. I don't know how to round this values before the clf.score.










share|improve this question




























    0














    I'm trying to do a linear regression in my dataframe. The dataframe is about apple applications, and I want to predict the notes of applications. The notes are in following format:



    1.0
    1.5
    2.0
    2.5
    ...
    5.0


    My code is:



    atributos = ['size_bytes','price','rating_count_tot','cont_rating','sup_devices_num','num_screenshots','num_lang','vpp_lic']
    atrib_prev = ['nota']

    X = np.array(data_regress.drop(['nota'],1))
    y = np.array(data_regress['nota'])

    X = preprocessing.scale(X)

    X_train, X_test, y_train, y_test = cross_validation.train_test_split(X, y, test_size=0.2)

    clf = LinearRegression()
    clf.fit(X_train, y_train)

    accuracy = clf.score(X_test, y_test)

    print(accuracy)


    But my accuracy is 0.046295306696438665. I think this occurs because the linear model is predicting real values, while my 'note' is real, but at intervals. I don't know how to round this values before the clf.score.










    share|improve this question


























      0












      0








      0







      I'm trying to do a linear regression in my dataframe. The dataframe is about apple applications, and I want to predict the notes of applications. The notes are in following format:



      1.0
      1.5
      2.0
      2.5
      ...
      5.0


      My code is:



      atributos = ['size_bytes','price','rating_count_tot','cont_rating','sup_devices_num','num_screenshots','num_lang','vpp_lic']
      atrib_prev = ['nota']

      X = np.array(data_regress.drop(['nota'],1))
      y = np.array(data_regress['nota'])

      X = preprocessing.scale(X)

      X_train, X_test, y_train, y_test = cross_validation.train_test_split(X, y, test_size=0.2)

      clf = LinearRegression()
      clf.fit(X_train, y_train)

      accuracy = clf.score(X_test, y_test)

      print(accuracy)


      But my accuracy is 0.046295306696438665. I think this occurs because the linear model is predicting real values, while my 'note' is real, but at intervals. I don't know how to round this values before the clf.score.










      share|improve this question















      I'm trying to do a linear regression in my dataframe. The dataframe is about apple applications, and I want to predict the notes of applications. The notes are in following format:



      1.0
      1.5
      2.0
      2.5
      ...
      5.0


      My code is:



      atributos = ['size_bytes','price','rating_count_tot','cont_rating','sup_devices_num','num_screenshots','num_lang','vpp_lic']
      atrib_prev = ['nota']

      X = np.array(data_regress.drop(['nota'],1))
      y = np.array(data_regress['nota'])

      X = preprocessing.scale(X)

      X_train, X_test, y_train, y_test = cross_validation.train_test_split(X, y, test_size=0.2)

      clf = LinearRegression()
      clf.fit(X_train, y_train)

      accuracy = clf.score(X_test, y_test)

      print(accuracy)


      But my accuracy is 0.046295306696438665. I think this occurs because the linear model is predicting real values, while my 'note' is real, but at intervals. I don't know how to round this values before the clf.score.







      pandas jupyter-notebook sklearn-pandas






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      edited Nov 14 '18 at 12:56









      Aqueous Carlos

      289213




      289213










      asked Nov 13 '18 at 0:10









      Giovanni Brogiato

      1




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          First, for regression models, clf.score() calculates R-squared value, not accuracy. So you would need to decide if you want to treat this problem as a classification problem (For some fixed number of target labels) or a regression problem (for a real-valued target)



          Secondly, if you insist on using regression models and not classification, you can call clf.predict() to first get the predicted values and then round off as you want to, and then call r2_score() on actual and predicted labels. Something like:



          # Get actual predictions
          y_pred = clf.predict(X_test)

          # You will need to implement the round function yourself
          y_pred_rounded = round(y_pred)

          # Call the appropriate scorer
          score = r2_score(y_test, y_pred_rounded)


          You can look at the sklearn documentation here for available metrics in sklearn.






          share|improve this answer




















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            1 Answer
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            1 Answer
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            active

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            active

            oldest

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            active

            oldest

            votes









            0














            First, for regression models, clf.score() calculates R-squared value, not accuracy. So you would need to decide if you want to treat this problem as a classification problem (For some fixed number of target labels) or a regression problem (for a real-valued target)



            Secondly, if you insist on using regression models and not classification, you can call clf.predict() to first get the predicted values and then round off as you want to, and then call r2_score() on actual and predicted labels. Something like:



            # Get actual predictions
            y_pred = clf.predict(X_test)

            # You will need to implement the round function yourself
            y_pred_rounded = round(y_pred)

            # Call the appropriate scorer
            score = r2_score(y_test, y_pred_rounded)


            You can look at the sklearn documentation here for available metrics in sklearn.






            share|improve this answer

























              0














              First, for regression models, clf.score() calculates R-squared value, not accuracy. So you would need to decide if you want to treat this problem as a classification problem (For some fixed number of target labels) or a regression problem (for a real-valued target)



              Secondly, if you insist on using regression models and not classification, you can call clf.predict() to first get the predicted values and then round off as you want to, and then call r2_score() on actual and predicted labels. Something like:



              # Get actual predictions
              y_pred = clf.predict(X_test)

              # You will need to implement the round function yourself
              y_pred_rounded = round(y_pred)

              # Call the appropriate scorer
              score = r2_score(y_test, y_pred_rounded)


              You can look at the sklearn documentation here for available metrics in sklearn.






              share|improve this answer























                0












                0








                0






                First, for regression models, clf.score() calculates R-squared value, not accuracy. So you would need to decide if you want to treat this problem as a classification problem (For some fixed number of target labels) or a regression problem (for a real-valued target)



                Secondly, if you insist on using regression models and not classification, you can call clf.predict() to first get the predicted values and then round off as you want to, and then call r2_score() on actual and predicted labels. Something like:



                # Get actual predictions
                y_pred = clf.predict(X_test)

                # You will need to implement the round function yourself
                y_pred_rounded = round(y_pred)

                # Call the appropriate scorer
                score = r2_score(y_test, y_pred_rounded)


                You can look at the sklearn documentation here for available metrics in sklearn.






                share|improve this answer












                First, for regression models, clf.score() calculates R-squared value, not accuracy. So you would need to decide if you want to treat this problem as a classification problem (For some fixed number of target labels) or a regression problem (for a real-valued target)



                Secondly, if you insist on using regression models and not classification, you can call clf.predict() to first get the predicted values and then round off as you want to, and then call r2_score() on actual and predicted labels. Something like:



                # Get actual predictions
                y_pred = clf.predict(X_test)

                # You will need to implement the round function yourself
                y_pred_rounded = round(y_pred)

                # Call the appropriate scorer
                score = r2_score(y_test, y_pred_rounded)


                You can look at the sklearn documentation here for available metrics in sklearn.







                share|improve this answer












                share|improve this answer



                share|improve this answer










                answered Nov 14 '18 at 14:25









                Vivek Kumar

                15.4k41952




                15.4k41952



























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