Check for an empty variable when using split() in python3

If I have for example a line of string like this:

line = alfa,bravo,zeta,cookie,dragonball

I can create them into a list like this:

parts = line.split(",")

However, I should be able to deal with an error if the line has "empty" objects, like in the following situations:

,coookie,dragonball,alfa
alfa,,dragonball,cookie
alfa,dragonball,cookie,

How can I do this? in case of an error, the line would not be included in a list, and the program would give an error message:

print("ERROR in line: ".format(line))

I thought about using a try/except, but I don't really know how it should be formatted in this case.

edited Nov 14 '18 at 15:08

asked Nov 14 '18 at 15:04

Astudent

538

1

What about checking for"" in line.split(",")?

– DocDriven
Nov 14 '18 at 15:08

You mean like this? if line.split(",") == "": #report error

– Astudent
Nov 14 '18 at 15:09

add a comment |

If I have for example a line of string like this:

line = alfa,bravo,zeta,cookie,dragonball

I can create them into a list like this:

parts = line.split(",")

However, I should be able to deal with an error if the line has "empty" objects, like in the following situations:

,coookie,dragonball,alfa
alfa,,dragonball,cookie
alfa,dragonball,cookie,

How can I do this? in case of an error, the line would not be included in a list, and the program would give an error message:

print("ERROR in line: ".format(line))

I thought about using a try/except, but I don't really know how it should be formatted in this case.

edited Nov 14 '18 at 15:08

asked Nov 14 '18 at 15:04

Astudent

538

1

What about checking for"" in line.split(",")?

– DocDriven
Nov 14 '18 at 15:08

You mean like this? if line.split(",") == "": #report error

– Astudent
Nov 14 '18 at 15:09

add a comment |

If I have for example a line of string like this:

line = alfa,bravo,zeta,cookie,dragonball

I can create them into a list like this:

parts = line.split(",")

However, I should be able to deal with an error if the line has "empty" objects, like in the following situations:

,coookie,dragonball,alfa
alfa,,dragonball,cookie
alfa,dragonball,cookie,

How can I do this? in case of an error, the line would not be included in a list, and the program would give an error message:

print("ERROR in line: ".format(line))

I thought about using a try/except, but I don't really know how it should be formatted in this case.

edited Nov 14 '18 at 15:08

asked Nov 14 '18 at 15:04

Astudent

538

If I have for example a line of string like this:

line = alfa,bravo,zeta,cookie,dragonball

I can create them into a list like this:

parts = line.split(",")

However, I should be able to deal with an error if the line has "empty" objects, like in the following situations:

,coookie,dragonball,alfa
alfa,,dragonball,cookie
alfa,dragonball,cookie,

How can I do this? in case of an error, the line would not be included in a list, and the program would give an error message:

print("ERROR in line: ".format(line))

I thought about using a try/except, but I don't really know how it should be formatted in this case.

python-3.x list error-handling split try-except

edited Nov 14 '18 at 15:08

asked Nov 14 '18 at 15:04

Astudent

538

edited Nov 14 '18 at 15:08

asked Nov 14 '18 at 15:04

Astudent

538

edited Nov 14 '18 at 15:08

asked Nov 14 '18 at 15:04

Astudent

538

asked Nov 14 '18 at 15:04

Astudent

538

asked Nov 14 '18 at 15:04

Astudent

538

1

What about checking for"" in line.split(",")?

– DocDriven
Nov 14 '18 at 15:08

You mean like this? if line.split(",") == "": #report error

– Astudent
Nov 14 '18 at 15:09

add a comment |

1

What about checking for"" in line.split(",")?

– DocDriven
Nov 14 '18 at 15:08

You mean like this? if line.split(",") == "": #report error

– Astudent
Nov 14 '18 at 15:09

What about checking for"" in line.split(",")?

– DocDriven
Nov 14 '18 at 15:08

You mean like this? if line.split(",") == "": #report error

– Astudent
Nov 14 '18 at 15:09

add a comment |

1 Answer
1

active

oldest

votes

Try this:

line = "alfa,bravo,zeta,cookie,dragonball"

if "" in line.split(","):

 print("ERROR in line: ".format(line))
 ## further error handling...

answered Nov 14 '18 at 15:13

DocDriven

1,1972620

1

Excellent answer. Thanks a lot!

– Astudent
Nov 14 '18 at 15:16

add a comment |

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1 Answer
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1 Answer
1

active

oldest

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Try this:

line = "alfa,bravo,zeta,cookie,dragonball"

if "" in line.split(","):

 print("ERROR in line: ".format(line))
 ## further error handling...

answered Nov 14 '18 at 15:13

DocDriven

1,1972620

1

Excellent answer. Thanks a lot!

– Astudent
Nov 14 '18 at 15:16

add a comment |

Try this:

line = "alfa,bravo,zeta,cookie,dragonball"

if "" in line.split(","):

 print("ERROR in line: ".format(line))
 ## further error handling...

answered Nov 14 '18 at 15:13

DocDriven

1,1972620

1

Excellent answer. Thanks a lot!

– Astudent
Nov 14 '18 at 15:16

add a comment |

Try this:

line = "alfa,bravo,zeta,cookie,dragonball"

if "" in line.split(","):

 print("ERROR in line: ".format(line))
 ## further error handling...

answered Nov 14 '18 at 15:13

DocDriven

1,1972620

Try this:

line = "alfa,bravo,zeta,cookie,dragonball"

if "" in line.split(","):

 print("ERROR in line: ".format(line))
 ## further error handling...

answered Nov 14 '18 at 15:13

DocDriven

1,1972620

answered Nov 14 '18 at 15:13

DocDriven

1,1972620

answered Nov 14 '18 at 15:13

DocDriven

1,1972620

answered Nov 14 '18 at 15:13

DocDriven

1,1972620

1

Excellent answer. Thanks a lot!

– Astudent
Nov 14 '18 at 15:16

add a comment |

1

Excellent answer. Thanks a lot!

– Astudent
Nov 14 '18 at 15:16

Excellent answer. Thanks a lot!

– Astudent
Nov 14 '18 at 15:16

add a comment |

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