Check for an empty variable when using split() in python3
If I have for example a line of string like this:
line = alfa,bravo,zeta,cookie,dragonball
I can create them into a list like this:
parts = line.split(",")
However, I should be able to deal with an error if the line has "empty" objects, like in the following situations:
,coookie,dragonball,alfa
alfa,,dragonball,cookie
alfa,dragonball,cookie,
How can I do this? in case of an error, the line would not be included in a list, and the program would give an error message:
print("ERROR in line: ".format(line))
I thought about using a try/except, but I don't really know how it should be formatted in this case.
python-3.x list error-handling split try-except
asked Nov 14 '18 at 15:04
AstudentAstudent
538
add a comment |
If I have for example a line of string like this:
line = alfa,bravo,zeta,cookie,dragonball
I can create them into a list like this:
parts = line.split(",")
However, I should be able to deal with an error if the line has "empty" objects, like in the following situations:
,coookie,dragonball,alfa
alfa,,dragonball,cookie
alfa,dragonball,cookie,
How can I do this? in case of an error, the line would not be included in a list, and the program would give an error message:
print("ERROR in line: ".format(line))
I thought about using a try/except, but I don't really know how it should be formatted in this case.
python-3.x list error-handling split try-except
asked Nov 14 '18 at 15:04
AstudentAstudent
538
1
What about checking for"" in line.split(",")?
– DocDriven
Nov 14 '18 at 15:08
You mean like this? if line.split(",") == "": #report error
– Astudent
Nov 14 '18 at 15:09
add a comment |
If I have for example a line of string like this:
line = alfa,bravo,zeta,cookie,dragonball
I can create them into a list like this:
parts = line.split(",")
However, I should be able to deal with an error if the line has "empty" objects, like in the following situations:
,coookie,dragonball,alfa
alfa,,dragonball,cookie
alfa,dragonball,cookie,
How can I do this? in case of an error, the line would not be included in a list, and the program would give an error message:
print("ERROR in line: ".format(line))
I thought about using a try/except, but I don't really know how it should be formatted in this case.
python-3.x list error-handling split try-except
asked Nov 14 '18 at 15:04
AstudentAstudent
538
If I have for example a line of string like this:
line = alfa,bravo,zeta,cookie,dragonball
I can create them into a list like this:
parts = line.split(",")
However, I should be able to deal with an error if the line has "empty" objects, like in the following situations:
,coookie,dragonball,alfa
alfa,,dragonball,cookie
alfa,dragonball,cookie,
How can I do this? in case of an error, the line would not be included in a list, and the program would give an error message:
print("ERROR in line: ".format(line))
I thought about using a try/except, but I don't really know how it should be formatted in this case.
python-3.x list error-handling split try-except
python-3.x list error-handling split try-except
asked Nov 14 '18 at 15:04
AstudentAstudent
538
asked Nov 14 '18 at 15:04
AstudentAstudent
538
edited Nov 14 '18 at 15:08
Astudent
asked Nov 14 '18 at 15:04
AstudentAstudent
538
asked Nov 14 '18 at 15:04
AstudentAstudent
538
asked Nov 14 '18 at 15:04
AstudentAstudent
538
538
1
What about checking for"" in line.split(",")?
– DocDriven
Nov 14 '18 at 15:08
You mean like this? if line.split(",") == "": #report error
– Astudent
Nov 14 '18 at 15:09
add a comment |
1
What about checking for"" in line.split(",")?
– DocDriven
Nov 14 '18 at 15:08
You mean like this? if line.split(",") == "": #report error
– Astudent
Nov 14 '18 at 15:09
1
1
What about checking for
"" in line.split(",")?– DocDriven
Nov 14 '18 at 15:08
What about checking for
"" in line.split(",")?– DocDriven
Nov 14 '18 at 15:08
You mean like this? if line.split(",") == "": #report error
– Astudent
Nov 14 '18 at 15:09
You mean like this? if line.split(",") == "": #report error
– Astudent
Nov 14 '18 at 15:09
add a comment |
1 Answer
1
active
oldest
votes
Try this:
line = "alfa,bravo,zeta,cookie,dragonball"
if "" in line.split(","):
print("ERROR in line: ".format(line))
## further error handling...
answered Nov 14 '18 at 15:13
DocDrivenDocDriven
1,1972620
1
Excellent answer. Thanks a lot!
– Astudent
Nov 14 '18 at 15:16
add a comment |
Your Answer
StackExchange.ifUsing("editor", function ()
StackExchange.using("externalEditor", function ()
StackExchange.using("snippets", function ()
StackExchange.snippets.init();
);
);
, "code-snippets");
StackExchange.ready(function()
var channelOptions =
tags: "".split(" "),
id: "1"
;
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function()
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled)
StackExchange.using("snippets", function()
createEditor();
);
else
createEditor();
);
function createEditor()
StackExchange.prepareEditor(
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader:
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
,
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
);
);
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53303188%2fcheck-for-an-empty-variable-when-using-split-in-python3%23new-answer', 'question_page');
);
Post as a guest
Required, but never shown
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
Try this:
line = "alfa,bravo,zeta,cookie,dragonball"
if "" in line.split(","):
print("ERROR in line: ".format(line))
## further error handling...
answered Nov 14 '18 at 15:13
DocDrivenDocDriven
1,1972620
1
Excellent answer. Thanks a lot!
– Astudent
Nov 14 '18 at 15:16
add a comment |
Try this:
line = "alfa,bravo,zeta,cookie,dragonball"
if "" in line.split(","):
print("ERROR in line: ".format(line))
## further error handling...
answered Nov 14 '18 at 15:13
DocDrivenDocDriven
1,1972620
1
Excellent answer. Thanks a lot!
– Astudent
Nov 14 '18 at 15:16
add a comment |
Try this:
line = "alfa,bravo,zeta,cookie,dragonball"
if "" in line.split(","):
print("ERROR in line: ".format(line))
## further error handling...
answered Nov 14 '18 at 15:13
DocDrivenDocDriven
1,1972620
Try this:
line = "alfa,bravo,zeta,cookie,dragonball"
if "" in line.split(","):
print("ERROR in line: ".format(line))
## further error handling...
answered Nov 14 '18 at 15:13
DocDrivenDocDriven
1,1972620
answered Nov 14 '18 at 15:13
DocDrivenDocDriven
1,1972620
answered Nov 14 '18 at 15:13
DocDrivenDocDriven
1,1972620
answered Nov 14 '18 at 15:13
DocDrivenDocDriven
1,1972620
1,1972620
1
Excellent answer. Thanks a lot!
– Astudent
Nov 14 '18 at 15:16
add a comment |
1
Excellent answer. Thanks a lot!
– Astudent
Nov 14 '18 at 15:16
1
1
Excellent answer. Thanks a lot!
– Astudent
Nov 14 '18 at 15:16
Excellent answer. Thanks a lot!
– Astudent
Nov 14 '18 at 15:16
add a comment |
Thanks for contributing an answer to Stack Overflow!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53303188%2fcheck-for-an-empty-variable-when-using-split-in-python3%23new-answer', 'question_page');
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
1
What about checking for
"" in line.split(",")?– DocDriven
Nov 14 '18 at 15:08
You mean like this? if line.split(",") == "": #report error
– Astudent
Nov 14 '18 at 15:09