PyMC3 passing stochastic covariance matrix to pm.MvNormal()
I've tried to fit a simple 2D gaussian model to observed data by using PyMC3.
import numpy as np
import pymc3 as pm
n = 10000;
np.random.seed(0)
X = np.random.multivariate_normal([0,0], [[1,0],[0,1]], n);
with pm.Model() as model:
# PRIORS
mu = [pm.Uniform('mux', lower=-1, upper=1),
pm.Uniform('muy', lower=-1, upper=1)]
cov = np.array([[pm.Uniform('a11', lower=0.1, upper=2), 0],
[0, pm.Uniform('a22', lower=0.1, upper=2)]])
# LIKELIHOOD
likelihood = pm.MvNormal('likelihood', mu=mu, cov=cov, observed=X)
with model:
trace = pm.sample(draws=1000, chains=2, tune=1000)
while I can do this in 1D by passing the sd
to pm.Normal
, I have some trouble in passing the covariance matrix to pm.MvNormal
.
Where am I going wrong?
python theano bayesian normal-distribution pymc3
add a comment |
I've tried to fit a simple 2D gaussian model to observed data by using PyMC3.
import numpy as np
import pymc3 as pm
n = 10000;
np.random.seed(0)
X = np.random.multivariate_normal([0,0], [[1,0],[0,1]], n);
with pm.Model() as model:
# PRIORS
mu = [pm.Uniform('mux', lower=-1, upper=1),
pm.Uniform('muy', lower=-1, upper=1)]
cov = np.array([[pm.Uniform('a11', lower=0.1, upper=2), 0],
[0, pm.Uniform('a22', lower=0.1, upper=2)]])
# LIKELIHOOD
likelihood = pm.MvNormal('likelihood', mu=mu, cov=cov, observed=X)
with model:
trace = pm.sample(draws=1000, chains=2, tune=1000)
while I can do this in 1D by passing the sd
to pm.Normal
, I have some trouble in passing the covariance matrix to pm.MvNormal
.
Where am I going wrong?
python theano bayesian normal-distribution pymc3
add a comment |
I've tried to fit a simple 2D gaussian model to observed data by using PyMC3.
import numpy as np
import pymc3 as pm
n = 10000;
np.random.seed(0)
X = np.random.multivariate_normal([0,0], [[1,0],[0,1]], n);
with pm.Model() as model:
# PRIORS
mu = [pm.Uniform('mux', lower=-1, upper=1),
pm.Uniform('muy', lower=-1, upper=1)]
cov = np.array([[pm.Uniform('a11', lower=0.1, upper=2), 0],
[0, pm.Uniform('a22', lower=0.1, upper=2)]])
# LIKELIHOOD
likelihood = pm.MvNormal('likelihood', mu=mu, cov=cov, observed=X)
with model:
trace = pm.sample(draws=1000, chains=2, tune=1000)
while I can do this in 1D by passing the sd
to pm.Normal
, I have some trouble in passing the covariance matrix to pm.MvNormal
.
Where am I going wrong?
python theano bayesian normal-distribution pymc3
I've tried to fit a simple 2D gaussian model to observed data by using PyMC3.
import numpy as np
import pymc3 as pm
n = 10000;
np.random.seed(0)
X = np.random.multivariate_normal([0,0], [[1,0],[0,1]], n);
with pm.Model() as model:
# PRIORS
mu = [pm.Uniform('mux', lower=-1, upper=1),
pm.Uniform('muy', lower=-1, upper=1)]
cov = np.array([[pm.Uniform('a11', lower=0.1, upper=2), 0],
[0, pm.Uniform('a22', lower=0.1, upper=2)]])
# LIKELIHOOD
likelihood = pm.MvNormal('likelihood', mu=mu, cov=cov, observed=X)
with model:
trace = pm.sample(draws=1000, chains=2, tune=1000)
while I can do this in 1D by passing the sd
to pm.Normal
, I have some trouble in passing the covariance matrix to pm.MvNormal
.
Where am I going wrong?
python theano bayesian normal-distribution pymc3
python theano bayesian normal-distribution pymc3
edited Nov 14 '18 at 22:42
merv
25.2k673109
25.2k673109
asked Nov 9 '18 at 9:05
FabioFabio
1335
1335
add a comment |
add a comment |
1 Answer
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PyMC3 distribution objects are not simple numeric objects or numpy arrays. Instead, they are nodes in a theano computation graph and often require operations from either pymc3.math
or theano.tensor
to manipulate them. Moreover, placing PyMC3 objects in numpy arrays is unnecessary since they already are multidimensional.
Original Model
Keeping with the intent of your code, a working version would go something like
import numpy as np
import pymc3 as pm
import theano.tensor as tt
N = 10000
np.random.seed(0)
X = np.random.multivariate_normal(np.zeros(2), np.eye(2), size=N)
with pm.Model() as model:
# use `shape` argument to define tensor dimensions
mu = pm.Uniform('mu', lower=-1, upper=1, shape=2)
# diagonal values on covariance matrix
a = pm.Uniform('a', lower=0.1, upper=2, shape=2)
# convert vector to a 2x2 matrix with `a` on the diagonal
cov = tt.diag(a)
likelihood = pm.MvNormal('likelihood', mu=mu, cov=cov, observed=X)
Alternative Model
I assume the example you provided is just a toy to communicate the problem. But just in case, I'll mention that the main advantage of using a multivariate normal (modeling covariance between parameters) is lost when restricting the covariance matrix to be diagonal. Furthermore, the theory of priors for covariance matrices is well-developed, so it's worth one's time considering existing solutions. In particular, there is a PyMC3 example using the LKJ prior for covariance matrices.
Here's a simple application of that example in this context:
with pm.Model() as model_lkj:
# use `shape` argument to define tensor dimensions
mu = pm.Uniform('mu', lower=-1, upper=1, shape=2)
# LKJ prior for covariance matrix (see example)
packed_L = pm.LKJCholeskyCov('packed_L', n=2,
eta=2., sd_dist=pm.HalfCauchy.dist(2.5))
# convert to (2,2)
L = pm.expand_packed_triangular(2, packed_L)
likelihood = pm.MvNormal('likelihood', mu=mu, chol=L, observed=X)
merv, thanks for the answer. Mine example was a toy model and I could use other ways as you suggested. In general I have difficulties in understanding how to include in the model custom operators. I have a topic similar on discourse.pymc.io/t/… where I have problem in including a "physical law" for the stochastic mean.
– Fabio
Nov 15 '18 at 18:32
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
PyMC3 distribution objects are not simple numeric objects or numpy arrays. Instead, they are nodes in a theano computation graph and often require operations from either pymc3.math
or theano.tensor
to manipulate them. Moreover, placing PyMC3 objects in numpy arrays is unnecessary since they already are multidimensional.
Original Model
Keeping with the intent of your code, a working version would go something like
import numpy as np
import pymc3 as pm
import theano.tensor as tt
N = 10000
np.random.seed(0)
X = np.random.multivariate_normal(np.zeros(2), np.eye(2), size=N)
with pm.Model() as model:
# use `shape` argument to define tensor dimensions
mu = pm.Uniform('mu', lower=-1, upper=1, shape=2)
# diagonal values on covariance matrix
a = pm.Uniform('a', lower=0.1, upper=2, shape=2)
# convert vector to a 2x2 matrix with `a` on the diagonal
cov = tt.diag(a)
likelihood = pm.MvNormal('likelihood', mu=mu, cov=cov, observed=X)
Alternative Model
I assume the example you provided is just a toy to communicate the problem. But just in case, I'll mention that the main advantage of using a multivariate normal (modeling covariance between parameters) is lost when restricting the covariance matrix to be diagonal. Furthermore, the theory of priors for covariance matrices is well-developed, so it's worth one's time considering existing solutions. In particular, there is a PyMC3 example using the LKJ prior for covariance matrices.
Here's a simple application of that example in this context:
with pm.Model() as model_lkj:
# use `shape` argument to define tensor dimensions
mu = pm.Uniform('mu', lower=-1, upper=1, shape=2)
# LKJ prior for covariance matrix (see example)
packed_L = pm.LKJCholeskyCov('packed_L', n=2,
eta=2., sd_dist=pm.HalfCauchy.dist(2.5))
# convert to (2,2)
L = pm.expand_packed_triangular(2, packed_L)
likelihood = pm.MvNormal('likelihood', mu=mu, chol=L, observed=X)
merv, thanks for the answer. Mine example was a toy model and I could use other ways as you suggested. In general I have difficulties in understanding how to include in the model custom operators. I have a topic similar on discourse.pymc.io/t/… where I have problem in including a "physical law" for the stochastic mean.
– Fabio
Nov 15 '18 at 18:32
add a comment |
PyMC3 distribution objects are not simple numeric objects or numpy arrays. Instead, they are nodes in a theano computation graph and often require operations from either pymc3.math
or theano.tensor
to manipulate them. Moreover, placing PyMC3 objects in numpy arrays is unnecessary since they already are multidimensional.
Original Model
Keeping with the intent of your code, a working version would go something like
import numpy as np
import pymc3 as pm
import theano.tensor as tt
N = 10000
np.random.seed(0)
X = np.random.multivariate_normal(np.zeros(2), np.eye(2), size=N)
with pm.Model() as model:
# use `shape` argument to define tensor dimensions
mu = pm.Uniform('mu', lower=-1, upper=1, shape=2)
# diagonal values on covariance matrix
a = pm.Uniform('a', lower=0.1, upper=2, shape=2)
# convert vector to a 2x2 matrix with `a` on the diagonal
cov = tt.diag(a)
likelihood = pm.MvNormal('likelihood', mu=mu, cov=cov, observed=X)
Alternative Model
I assume the example you provided is just a toy to communicate the problem. But just in case, I'll mention that the main advantage of using a multivariate normal (modeling covariance between parameters) is lost when restricting the covariance matrix to be diagonal. Furthermore, the theory of priors for covariance matrices is well-developed, so it's worth one's time considering existing solutions. In particular, there is a PyMC3 example using the LKJ prior for covariance matrices.
Here's a simple application of that example in this context:
with pm.Model() as model_lkj:
# use `shape` argument to define tensor dimensions
mu = pm.Uniform('mu', lower=-1, upper=1, shape=2)
# LKJ prior for covariance matrix (see example)
packed_L = pm.LKJCholeskyCov('packed_L', n=2,
eta=2., sd_dist=pm.HalfCauchy.dist(2.5))
# convert to (2,2)
L = pm.expand_packed_triangular(2, packed_L)
likelihood = pm.MvNormal('likelihood', mu=mu, chol=L, observed=X)
merv, thanks for the answer. Mine example was a toy model and I could use other ways as you suggested. In general I have difficulties in understanding how to include in the model custom operators. I have a topic similar on discourse.pymc.io/t/… where I have problem in including a "physical law" for the stochastic mean.
– Fabio
Nov 15 '18 at 18:32
add a comment |
PyMC3 distribution objects are not simple numeric objects or numpy arrays. Instead, they are nodes in a theano computation graph and often require operations from either pymc3.math
or theano.tensor
to manipulate them. Moreover, placing PyMC3 objects in numpy arrays is unnecessary since they already are multidimensional.
Original Model
Keeping with the intent of your code, a working version would go something like
import numpy as np
import pymc3 as pm
import theano.tensor as tt
N = 10000
np.random.seed(0)
X = np.random.multivariate_normal(np.zeros(2), np.eye(2), size=N)
with pm.Model() as model:
# use `shape` argument to define tensor dimensions
mu = pm.Uniform('mu', lower=-1, upper=1, shape=2)
# diagonal values on covariance matrix
a = pm.Uniform('a', lower=0.1, upper=2, shape=2)
# convert vector to a 2x2 matrix with `a` on the diagonal
cov = tt.diag(a)
likelihood = pm.MvNormal('likelihood', mu=mu, cov=cov, observed=X)
Alternative Model
I assume the example you provided is just a toy to communicate the problem. But just in case, I'll mention that the main advantage of using a multivariate normal (modeling covariance between parameters) is lost when restricting the covariance matrix to be diagonal. Furthermore, the theory of priors for covariance matrices is well-developed, so it's worth one's time considering existing solutions. In particular, there is a PyMC3 example using the LKJ prior for covariance matrices.
Here's a simple application of that example in this context:
with pm.Model() as model_lkj:
# use `shape` argument to define tensor dimensions
mu = pm.Uniform('mu', lower=-1, upper=1, shape=2)
# LKJ prior for covariance matrix (see example)
packed_L = pm.LKJCholeskyCov('packed_L', n=2,
eta=2., sd_dist=pm.HalfCauchy.dist(2.5))
# convert to (2,2)
L = pm.expand_packed_triangular(2, packed_L)
likelihood = pm.MvNormal('likelihood', mu=mu, chol=L, observed=X)
PyMC3 distribution objects are not simple numeric objects or numpy arrays. Instead, they are nodes in a theano computation graph and often require operations from either pymc3.math
or theano.tensor
to manipulate them. Moreover, placing PyMC3 objects in numpy arrays is unnecessary since they already are multidimensional.
Original Model
Keeping with the intent of your code, a working version would go something like
import numpy as np
import pymc3 as pm
import theano.tensor as tt
N = 10000
np.random.seed(0)
X = np.random.multivariate_normal(np.zeros(2), np.eye(2), size=N)
with pm.Model() as model:
# use `shape` argument to define tensor dimensions
mu = pm.Uniform('mu', lower=-1, upper=1, shape=2)
# diagonal values on covariance matrix
a = pm.Uniform('a', lower=0.1, upper=2, shape=2)
# convert vector to a 2x2 matrix with `a` on the diagonal
cov = tt.diag(a)
likelihood = pm.MvNormal('likelihood', mu=mu, cov=cov, observed=X)
Alternative Model
I assume the example you provided is just a toy to communicate the problem. But just in case, I'll mention that the main advantage of using a multivariate normal (modeling covariance between parameters) is lost when restricting the covariance matrix to be diagonal. Furthermore, the theory of priors for covariance matrices is well-developed, so it's worth one's time considering existing solutions. In particular, there is a PyMC3 example using the LKJ prior for covariance matrices.
Here's a simple application of that example in this context:
with pm.Model() as model_lkj:
# use `shape` argument to define tensor dimensions
mu = pm.Uniform('mu', lower=-1, upper=1, shape=2)
# LKJ prior for covariance matrix (see example)
packed_L = pm.LKJCholeskyCov('packed_L', n=2,
eta=2., sd_dist=pm.HalfCauchy.dist(2.5))
# convert to (2,2)
L = pm.expand_packed_triangular(2, packed_L)
likelihood = pm.MvNormal('likelihood', mu=mu, chol=L, observed=X)
edited Nov 14 '18 at 21:59
answered Nov 14 '18 at 20:40
mervmerv
25.2k673109
25.2k673109
merv, thanks for the answer. Mine example was a toy model and I could use other ways as you suggested. In general I have difficulties in understanding how to include in the model custom operators. I have a topic similar on discourse.pymc.io/t/… where I have problem in including a "physical law" for the stochastic mean.
– Fabio
Nov 15 '18 at 18:32
add a comment |
merv, thanks for the answer. Mine example was a toy model and I could use other ways as you suggested. In general I have difficulties in understanding how to include in the model custom operators. I have a topic similar on discourse.pymc.io/t/… where I have problem in including a "physical law" for the stochastic mean.
– Fabio
Nov 15 '18 at 18:32
merv, thanks for the answer. Mine example was a toy model and I could use other ways as you suggested. In general I have difficulties in understanding how to include in the model custom operators. I have a topic similar on discourse.pymc.io/t/… where I have problem in including a "physical law" for the stochastic mean.
– Fabio
Nov 15 '18 at 18:32
merv, thanks for the answer. Mine example was a toy model and I could use other ways as you suggested. In general I have difficulties in understanding how to include in the model custom operators. I have a topic similar on discourse.pymc.io/t/… where I have problem in including a "physical law" for the stochastic mean.
– Fabio
Nov 15 '18 at 18:32
add a comment |
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