Replacing a part of a string with a randomly generated number
I have a string that looks something like that
my_string='TAG="0000" TAG="1111" TAG="2222"'
what I want to do is simply replace those numbers by randomly generated ones in my string.
I was consindering doing something like:
new_string = my_string.replace('0000',str(random.randint(1,1000000)))
This is very easy and it works. Now let's say I want to make it more dynamic (in case I have a very long string with many TAG elements), I want to tell the code: "Each time you find "TAG=" in my_string, replace the following number with a random one". Does anyone have an idea?
Thanks a lot.
python string random
asked Nov 15 '18 at 18:56
WhelanGWhelanG
6818
add a comment |
I have a string that looks something like that
my_string='TAG="0000" TAG="1111" TAG="2222"'
what I want to do is simply replace those numbers by randomly generated ones in my string.
I was consindering doing something like:
new_string = my_string.replace('0000',str(random.randint(1,1000000)))
This is very easy and it works. Now let's say I want to make it more dynamic (in case I have a very long string with many TAG elements), I want to tell the code: "Each time you find "TAG=" in my_string, replace the following number with a random one". Does anyone have an idea?
Thanks a lot.
python string random
asked Nov 15 '18 at 18:56
WhelanGWhelanG
6818
add a comment |
I have a string that looks something like that
my_string='TAG="0000" TAG="1111" TAG="2222"'
what I want to do is simply replace those numbers by randomly generated ones in my string.
I was consindering doing something like:
new_string = my_string.replace('0000',str(random.randint(1,1000000)))
This is very easy and it works. Now let's say I want to make it more dynamic (in case I have a very long string with many TAG elements), I want to tell the code: "Each time you find "TAG=" in my_string, replace the following number with a random one". Does anyone have an idea?
Thanks a lot.
python string random
asked Nov 15 '18 at 18:56
WhelanGWhelanG
6818
I have a string that looks something like that
my_string='TAG="0000" TAG="1111" TAG="2222"'
what I want to do is simply replace those numbers by randomly generated ones in my string.
I was consindering doing something like:
new_string = my_string.replace('0000',str(random.randint(1,1000000)))
This is very easy and it works. Now let's say I want to make it more dynamic (in case I have a very long string with many TAG elements), I want to tell the code: "Each time you find "TAG=" in my_string, replace the following number with a random one". Does anyone have an idea?
Thanks a lot.
python string random
python string random
asked Nov 15 '18 at 18:56
WhelanGWhelanG
6818
asked Nov 15 '18 at 18:56
WhelanGWhelanG
6818
asked Nov 15 '18 at 18:56
WhelanGWhelanG
6818
asked Nov 15 '18 at 18:56
WhelanGWhelanG
6818
asked Nov 15 '18 at 18:56
WhelanGWhelanG
6818
6818
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
You can use re.sub:
import re, random
my_string='TAG="0000" TAG="1111" TAG="2222"'
new_string = re.sub('(?<=TAG=")d+', lambda _:str(random.randint(1,1000000)), my_string)
Output:
'TAG="901888" TAG="940530" TAG="439872"'
answered Nov 15 '18 at 18:58
Ajax1234Ajax1234
42.1k42854
very nice! thanks a lot
– WhelanG
Nov 15 '18 at 22:16
add a comment |
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1 Answer
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1 Answer
1
active
oldest
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active
oldest
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active
oldest
votes
You can use re.sub:
import re, random
my_string='TAG="0000" TAG="1111" TAG="2222"'
new_string = re.sub('(?<=TAG=")d+', lambda _:str(random.randint(1,1000000)), my_string)
Output:
'TAG="901888" TAG="940530" TAG="439872"'
answered Nov 15 '18 at 18:58
Ajax1234Ajax1234
42.1k42854
very nice! thanks a lot
– WhelanG
Nov 15 '18 at 22:16
add a comment |
You can use re.sub:
import re, random
my_string='TAG="0000" TAG="1111" TAG="2222"'
new_string = re.sub('(?<=TAG=")d+', lambda _:str(random.randint(1,1000000)), my_string)
Output:
'TAG="901888" TAG="940530" TAG="439872"'
answered Nov 15 '18 at 18:58
Ajax1234Ajax1234
42.1k42854
very nice! thanks a lot
– WhelanG
Nov 15 '18 at 22:16
add a comment |
You can use re.sub:
import re, random
my_string='TAG="0000" TAG="1111" TAG="2222"'
new_string = re.sub('(?<=TAG=")d+', lambda _:str(random.randint(1,1000000)), my_string)
Output:
'TAG="901888" TAG="940530" TAG="439872"'
answered Nov 15 '18 at 18:58
Ajax1234Ajax1234
42.1k42854
You can use re.sub:
import re, random
my_string='TAG="0000" TAG="1111" TAG="2222"'
new_string = re.sub('(?<=TAG=")d+', lambda _:str(random.randint(1,1000000)), my_string)
Output:
'TAG="901888" TAG="940530" TAG="439872"'
answered Nov 15 '18 at 18:58
Ajax1234Ajax1234
42.1k42854
answered Nov 15 '18 at 18:58
Ajax1234Ajax1234
42.1k42854
answered Nov 15 '18 at 18:58
Ajax1234Ajax1234
42.1k42854
answered Nov 15 '18 at 18:58
Ajax1234Ajax1234
42.1k42854
42.1k42854
very nice! thanks a lot
– WhelanG
Nov 15 '18 at 22:16
add a comment |
very nice! thanks a lot
– WhelanG
Nov 15 '18 at 22:16
very nice! thanks a lot
– WhelanG
Nov 15 '18 at 22:16
very nice! thanks a lot
– WhelanG
Nov 15 '18 at 22:16
add a comment |
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