Delete selected rows in uitable - Matlab



.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty height:90px;width:728px;box-sizing:border-box;








0















I built in GUI (using GUIDE) a uitable (4x5) that last row is logical so I can select lines to delete.



d = 'L1',1,10,true;'L2',2,20,true;'L3',3,30,false;'L4',4,40,true;'L4',5,50,false;
set(handles.outputTable,'Data',d)


I created a button to delete the selectd rows but I does not work:



function deleteButton_Callback(hObject, eventdata, handles)
% hObject handle to deleteButton (see GCBO)
% eventdata reserved - to be defined in a future version of MATLAB
% handles structure with handles and user data (see GUIDATA)
dataTable = (get(handles.outputTable,'data'));

[m n] = size(dataTable);

disp(dataTable);

for i = 1:m
if num2str(cell2mat(dataTable(i,4))) =='1'
dataTable(i,:)=;
end
end

disp('Modifed table')
disp(dataTable);


How can I fix it so I get set the table again in the GUI?










share|improve this question






















  • (1) You first get the data from the uitable in your variable dataTable =>ok. Then (2) you modify the dataTable according to your needs => ok. Now you just need to complete the process: (3) push your dataTable back into the uitable, something like set(handles.outputTable,'data',dataTable).

    – Hoki
    Nov 16 '18 at 14:18











  • I get an error with the loop, the rows are not deleted. Any idea why?

    – wrek
    Nov 16 '18 at 14:28











  • you don't need num2str and cell2mat to just check for a boolean value in a cell array. You could try just checking for if dataTablei,4 ; dataTable(i,:)=; end. Note the use of the curly braces: ... instead of the parenthesis, when you want to retrieve the content of a given cell.

    – Hoki
    Nov 16 '18 at 14:42


















0















I built in GUI (using GUIDE) a uitable (4x5) that last row is logical so I can select lines to delete.



d = 'L1',1,10,true;'L2',2,20,true;'L3',3,30,false;'L4',4,40,true;'L4',5,50,false;
set(handles.outputTable,'Data',d)


I created a button to delete the selectd rows but I does not work:



function deleteButton_Callback(hObject, eventdata, handles)
% hObject handle to deleteButton (see GCBO)
% eventdata reserved - to be defined in a future version of MATLAB
% handles structure with handles and user data (see GUIDATA)
dataTable = (get(handles.outputTable,'data'));

[m n] = size(dataTable);

disp(dataTable);

for i = 1:m
if num2str(cell2mat(dataTable(i,4))) =='1'
dataTable(i,:)=;
end
end

disp('Modifed table')
disp(dataTable);


How can I fix it so I get set the table again in the GUI?










share|improve this question






















  • (1) You first get the data from the uitable in your variable dataTable =>ok. Then (2) you modify the dataTable according to your needs => ok. Now you just need to complete the process: (3) push your dataTable back into the uitable, something like set(handles.outputTable,'data',dataTable).

    – Hoki
    Nov 16 '18 at 14:18











  • I get an error with the loop, the rows are not deleted. Any idea why?

    – wrek
    Nov 16 '18 at 14:28











  • you don't need num2str and cell2mat to just check for a boolean value in a cell array. You could try just checking for if dataTablei,4 ; dataTable(i,:)=; end. Note the use of the curly braces: ... instead of the parenthesis, when you want to retrieve the content of a given cell.

    – Hoki
    Nov 16 '18 at 14:42














0












0








0








I built in GUI (using GUIDE) a uitable (4x5) that last row is logical so I can select lines to delete.



d = 'L1',1,10,true;'L2',2,20,true;'L3',3,30,false;'L4',4,40,true;'L4',5,50,false;
set(handles.outputTable,'Data',d)


I created a button to delete the selectd rows but I does not work:



function deleteButton_Callback(hObject, eventdata, handles)
% hObject handle to deleteButton (see GCBO)
% eventdata reserved - to be defined in a future version of MATLAB
% handles structure with handles and user data (see GUIDATA)
dataTable = (get(handles.outputTable,'data'));

[m n] = size(dataTable);

disp(dataTable);

for i = 1:m
if num2str(cell2mat(dataTable(i,4))) =='1'
dataTable(i,:)=;
end
end

disp('Modifed table')
disp(dataTable);


How can I fix it so I get set the table again in the GUI?










share|improve this question














I built in GUI (using GUIDE) a uitable (4x5) that last row is logical so I can select lines to delete.



d = 'L1',1,10,true;'L2',2,20,true;'L3',3,30,false;'L4',4,40,true;'L4',5,50,false;
set(handles.outputTable,'Data',d)


I created a button to delete the selectd rows but I does not work:



function deleteButton_Callback(hObject, eventdata, handles)
% hObject handle to deleteButton (see GCBO)
% eventdata reserved - to be defined in a future version of MATLAB
% handles structure with handles and user data (see GUIDATA)
dataTable = (get(handles.outputTable,'data'));

[m n] = size(dataTable);

disp(dataTable);

for i = 1:m
if num2str(cell2mat(dataTable(i,4))) =='1'
dataTable(i,:)=;
end
end

disp('Modifed table')
disp(dataTable);


How can I fix it so I get set the table again in the GUI?







matlab






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked Nov 16 '18 at 13:45









wrekwrek

1148




1148












  • (1) You first get the data from the uitable in your variable dataTable =>ok. Then (2) you modify the dataTable according to your needs => ok. Now you just need to complete the process: (3) push your dataTable back into the uitable, something like set(handles.outputTable,'data',dataTable).

    – Hoki
    Nov 16 '18 at 14:18











  • I get an error with the loop, the rows are not deleted. Any idea why?

    – wrek
    Nov 16 '18 at 14:28











  • you don't need num2str and cell2mat to just check for a boolean value in a cell array. You could try just checking for if dataTablei,4 ; dataTable(i,:)=; end. Note the use of the curly braces: ... instead of the parenthesis, when you want to retrieve the content of a given cell.

    – Hoki
    Nov 16 '18 at 14:42


















  • (1) You first get the data from the uitable in your variable dataTable =>ok. Then (2) you modify the dataTable according to your needs => ok. Now you just need to complete the process: (3) push your dataTable back into the uitable, something like set(handles.outputTable,'data',dataTable).

    – Hoki
    Nov 16 '18 at 14:18











  • I get an error with the loop, the rows are not deleted. Any idea why?

    – wrek
    Nov 16 '18 at 14:28











  • you don't need num2str and cell2mat to just check for a boolean value in a cell array. You could try just checking for if dataTablei,4 ; dataTable(i,:)=; end. Note the use of the curly braces: ... instead of the parenthesis, when you want to retrieve the content of a given cell.

    – Hoki
    Nov 16 '18 at 14:42

















(1) You first get the data from the uitable in your variable dataTable =>ok. Then (2) you modify the dataTable according to your needs => ok. Now you just need to complete the process: (3) push your dataTable back into the uitable, something like set(handles.outputTable,'data',dataTable).

– Hoki
Nov 16 '18 at 14:18





(1) You first get the data from the uitable in your variable dataTable =>ok. Then (2) you modify the dataTable according to your needs => ok. Now you just need to complete the process: (3) push your dataTable back into the uitable, something like set(handles.outputTable,'data',dataTable).

– Hoki
Nov 16 '18 at 14:18













I get an error with the loop, the rows are not deleted. Any idea why?

– wrek
Nov 16 '18 at 14:28





I get an error with the loop, the rows are not deleted. Any idea why?

– wrek
Nov 16 '18 at 14:28













you don't need num2str and cell2mat to just check for a boolean value in a cell array. You could try just checking for if dataTablei,4 ; dataTable(i,:)=; end. Note the use of the curly braces: ... instead of the parenthesis, when you want to retrieve the content of a given cell.

– Hoki
Nov 16 '18 at 14:42






you don't need num2str and cell2mat to just check for a boolean value in a cell array. You could try just checking for if dataTablei,4 ; dataTable(i,:)=; end. Note the use of the curly braces: ... instead of the parenthesis, when you want to retrieve the content of a given cell.

– Hoki
Nov 16 '18 at 14:42













1 Answer
1






active

oldest

votes


















1














This is wrong:



for i = 1:m
if num2str(cell2mat(dataTable(i,4))) =='1'
dataTable(i,:)=;
end
end


First of all, if num2str(cell2mat(dataTable(i,4))) =='1' is a convoluted equivalent of if dataTablei,4==1. You should learn to use curly braces to access the content of a cell array.



Then, it will work only if the counter is decreased.
See what happens:



Test if row n should be deleted
Delete line n; the content of row (n+1) have now moved to row n
Increment counter i from value n to n+1
The row now at position n has never been tested for deletion !


What was at row (n+1) is never tested, since the delete operation moves it backwards first, then the counter is incremented without testing again. The solution is to decrement the counter.



for i = m:-1:1
if dataTablei,4
dataTable(i,:)=;
end
end


The rows moved by the deletion operation have already been tested, so in the end it is certain that all lines will have been tested.



Now, the same can be obtained in a vectorized form with a single line:



dataTable = dataTable(cell2mat(dataTable(:,4))==0,:);


The whole function boils down to:



function deleteButton_Callback(hObject, eventdata, handles)
dataTable = get(handles.outputTable,'data');
% Do some checks to make sure that the values input by are correct %
assert(all(cellfun(@isscalar,dataTable(:,4))), 'Last colum should contain scalars!');
set(handles.outputTable,'data' , dataTable(cell2mat(dataTable(:,4))==0,:));
end





share|improve this answer























    Your Answer






    StackExchange.ifUsing("editor", function ()
    StackExchange.using("externalEditor", function ()
    StackExchange.using("snippets", function ()
    StackExchange.snippets.init();
    );
    );
    , "code-snippets");

    StackExchange.ready(function()
    var channelOptions =
    tags: "".split(" "),
    id: "1"
    ;
    initTagRenderer("".split(" "), "".split(" "), channelOptions);

    StackExchange.using("externalEditor", function()
    // Have to fire editor after snippets, if snippets enabled
    if (StackExchange.settings.snippets.snippetsEnabled)
    StackExchange.using("snippets", function()
    createEditor();
    );

    else
    createEditor();

    );

    function createEditor()
    StackExchange.prepareEditor(
    heartbeatType: 'answer',
    autoActivateHeartbeat: false,
    convertImagesToLinks: true,
    noModals: true,
    showLowRepImageUploadWarning: true,
    reputationToPostImages: 10,
    bindNavPrevention: true,
    postfix: "",
    imageUploader:
    brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
    contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
    allowUrls: true
    ,
    onDemand: true,
    discardSelector: ".discard-answer"
    ,immediatelyShowMarkdownHelp:true
    );



    );













    draft saved

    draft discarded


















    StackExchange.ready(
    function ()
    StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53339097%2fdelete-selected-rows-in-uitable-matlab%23new-answer', 'question_page');

    );

    Post as a guest















    Required, but never shown

























    1 Answer
    1






    active

    oldest

    votes








    1 Answer
    1






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    1














    This is wrong:



    for i = 1:m
    if num2str(cell2mat(dataTable(i,4))) =='1'
    dataTable(i,:)=;
    end
    end


    First of all, if num2str(cell2mat(dataTable(i,4))) =='1' is a convoluted equivalent of if dataTablei,4==1. You should learn to use curly braces to access the content of a cell array.



    Then, it will work only if the counter is decreased.
    See what happens:



    Test if row n should be deleted
    Delete line n; the content of row (n+1) have now moved to row n
    Increment counter i from value n to n+1
    The row now at position n has never been tested for deletion !


    What was at row (n+1) is never tested, since the delete operation moves it backwards first, then the counter is incremented without testing again. The solution is to decrement the counter.



    for i = m:-1:1
    if dataTablei,4
    dataTable(i,:)=;
    end
    end


    The rows moved by the deletion operation have already been tested, so in the end it is certain that all lines will have been tested.



    Now, the same can be obtained in a vectorized form with a single line:



    dataTable = dataTable(cell2mat(dataTable(:,4))==0,:);


    The whole function boils down to:



    function deleteButton_Callback(hObject, eventdata, handles)
    dataTable = get(handles.outputTable,'data');
    % Do some checks to make sure that the values input by are correct %
    assert(all(cellfun(@isscalar,dataTable(:,4))), 'Last colum should contain scalars!');
    set(handles.outputTable,'data' , dataTable(cell2mat(dataTable(:,4))==0,:));
    end





    share|improve this answer



























      1














      This is wrong:



      for i = 1:m
      if num2str(cell2mat(dataTable(i,4))) =='1'
      dataTable(i,:)=;
      end
      end


      First of all, if num2str(cell2mat(dataTable(i,4))) =='1' is a convoluted equivalent of if dataTablei,4==1. You should learn to use curly braces to access the content of a cell array.



      Then, it will work only if the counter is decreased.
      See what happens:



      Test if row n should be deleted
      Delete line n; the content of row (n+1) have now moved to row n
      Increment counter i from value n to n+1
      The row now at position n has never been tested for deletion !


      What was at row (n+1) is never tested, since the delete operation moves it backwards first, then the counter is incremented without testing again. The solution is to decrement the counter.



      for i = m:-1:1
      if dataTablei,4
      dataTable(i,:)=;
      end
      end


      The rows moved by the deletion operation have already been tested, so in the end it is certain that all lines will have been tested.



      Now, the same can be obtained in a vectorized form with a single line:



      dataTable = dataTable(cell2mat(dataTable(:,4))==0,:);


      The whole function boils down to:



      function deleteButton_Callback(hObject, eventdata, handles)
      dataTable = get(handles.outputTable,'data');
      % Do some checks to make sure that the values input by are correct %
      assert(all(cellfun(@isscalar,dataTable(:,4))), 'Last colum should contain scalars!');
      set(handles.outputTable,'data' , dataTable(cell2mat(dataTable(:,4))==0,:));
      end





      share|improve this answer

























        1












        1








        1







        This is wrong:



        for i = 1:m
        if num2str(cell2mat(dataTable(i,4))) =='1'
        dataTable(i,:)=;
        end
        end


        First of all, if num2str(cell2mat(dataTable(i,4))) =='1' is a convoluted equivalent of if dataTablei,4==1. You should learn to use curly braces to access the content of a cell array.



        Then, it will work only if the counter is decreased.
        See what happens:



        Test if row n should be deleted
        Delete line n; the content of row (n+1) have now moved to row n
        Increment counter i from value n to n+1
        The row now at position n has never been tested for deletion !


        What was at row (n+1) is never tested, since the delete operation moves it backwards first, then the counter is incremented without testing again. The solution is to decrement the counter.



        for i = m:-1:1
        if dataTablei,4
        dataTable(i,:)=;
        end
        end


        The rows moved by the deletion operation have already been tested, so in the end it is certain that all lines will have been tested.



        Now, the same can be obtained in a vectorized form with a single line:



        dataTable = dataTable(cell2mat(dataTable(:,4))==0,:);


        The whole function boils down to:



        function deleteButton_Callback(hObject, eventdata, handles)
        dataTable = get(handles.outputTable,'data');
        % Do some checks to make sure that the values input by are correct %
        assert(all(cellfun(@isscalar,dataTable(:,4))), 'Last colum should contain scalars!');
        set(handles.outputTable,'data' , dataTable(cell2mat(dataTable(:,4))==0,:));
        end





        share|improve this answer













        This is wrong:



        for i = 1:m
        if num2str(cell2mat(dataTable(i,4))) =='1'
        dataTable(i,:)=;
        end
        end


        First of all, if num2str(cell2mat(dataTable(i,4))) =='1' is a convoluted equivalent of if dataTablei,4==1. You should learn to use curly braces to access the content of a cell array.



        Then, it will work only if the counter is decreased.
        See what happens:



        Test if row n should be deleted
        Delete line n; the content of row (n+1) have now moved to row n
        Increment counter i from value n to n+1
        The row now at position n has never been tested for deletion !


        What was at row (n+1) is never tested, since the delete operation moves it backwards first, then the counter is incremented without testing again. The solution is to decrement the counter.



        for i = m:-1:1
        if dataTablei,4
        dataTable(i,:)=;
        end
        end


        The rows moved by the deletion operation have already been tested, so in the end it is certain that all lines will have been tested.



        Now, the same can be obtained in a vectorized form with a single line:



        dataTable = dataTable(cell2mat(dataTable(:,4))==0,:);


        The whole function boils down to:



        function deleteButton_Callback(hObject, eventdata, handles)
        dataTable = get(handles.outputTable,'data');
        % Do some checks to make sure that the values input by are correct %
        assert(all(cellfun(@isscalar,dataTable(:,4))), 'Last colum should contain scalars!');
        set(handles.outputTable,'data' , dataTable(cell2mat(dataTable(:,4))==0,:));
        end






        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Nov 16 '18 at 15:25









        BriceBrice

        1,416110




        1,416110





























            draft saved

            draft discarded
















































            Thanks for contributing an answer to Stack Overflow!


            • Please be sure to answer the question. Provide details and share your research!

            But avoid


            • Asking for help, clarification, or responding to other answers.

            • Making statements based on opinion; back them up with references or personal experience.

            To learn more, see our tips on writing great answers.




            draft saved


            draft discarded














            StackExchange.ready(
            function ()
            StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53339097%2fdelete-selected-rows-in-uitable-matlab%23new-answer', 'question_page');

            );

            Post as a guest















            Required, but never shown





















































            Required, but never shown














            Required, but never shown












            Required, but never shown







            Required, but never shown

































            Required, but never shown














            Required, but never shown












            Required, but never shown







            Required, but never shown







            Popular posts from this blog

            Top Tejano songwriter Luis Silva dead of heart attack at 64

            政党

            天津地下鉄3号線