jackson polymorphic deserialization with a custom criteria
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I need to know whether I can deserialize a generic object to it's defining type without having an additional property or without mentioning the type in an annotation.
Ex:-
@JsonTypeInfo(use=JsonTypeInfo.Id.CLASS, include=JsonTypeInfo.As.PROPERTY, property="@class")
In above I have to mention the @class property, and another way is
@JsonTypeInfo(use = JsonTypeInfo.Id.NAME, include = JsonTypeInfo.As.PROPERTY)
@JsonSubTypes(
@JsonSubTypes.Type(value = Dog.class, name = "Dog"),
@JsonSubTypes.Type(value = Cat.class, name = "Cat")
)
in the above example, we are defining the subclasses and a custom type.
Using a custome deserializer StdDeserializer<T>
Is there any other way to do this please tell me.
java json spring serialization jackson
asked Nov 16 '18 at 13:40
MaxExplodeMaxExplode
1,3021219
add a comment |
I need to know whether I can deserialize a generic object to it's defining type without having an additional property or without mentioning the type in an annotation.
Ex:-
@JsonTypeInfo(use=JsonTypeInfo.Id.CLASS, include=JsonTypeInfo.As.PROPERTY, property="@class")
In above I have to mention the @class property, and another way is
@JsonTypeInfo(use = JsonTypeInfo.Id.NAME, include = JsonTypeInfo.As.PROPERTY)
@JsonSubTypes(
@JsonSubTypes.Type(value = Dog.class, name = "Dog"),
@JsonSubTypes.Type(value = Cat.class, name = "Cat")
)
in the above example, we are defining the subclasses and a custom type.
Using a custome deserializer StdDeserializer<T>
Is there any other way to do this please tell me.
java json spring serialization jackson
asked Nov 16 '18 at 13:40
MaxExplodeMaxExplode
1,3021219
add a comment |
I need to know whether I can deserialize a generic object to it's defining type without having an additional property or without mentioning the type in an annotation.
Ex:-
@JsonTypeInfo(use=JsonTypeInfo.Id.CLASS, include=JsonTypeInfo.As.PROPERTY, property="@class")
In above I have to mention the @class property, and another way is
@JsonTypeInfo(use = JsonTypeInfo.Id.NAME, include = JsonTypeInfo.As.PROPERTY)
@JsonSubTypes(
@JsonSubTypes.Type(value = Dog.class, name = "Dog"),
@JsonSubTypes.Type(value = Cat.class, name = "Cat")
)
in the above example, we are defining the subclasses and a custom type.
Using a custome deserializer StdDeserializer<T>
Is there any other way to do this please tell me.
java json spring serialization jackson
asked Nov 16 '18 at 13:40
MaxExplodeMaxExplode
1,3021219
I need to know whether I can deserialize a generic object to it's defining type without having an additional property or without mentioning the type in an annotation.
Ex:-
@JsonTypeInfo(use=JsonTypeInfo.Id.CLASS, include=JsonTypeInfo.As.PROPERTY, property="@class")
In above I have to mention the @class property, and another way is
@JsonTypeInfo(use = JsonTypeInfo.Id.NAME, include = JsonTypeInfo.As.PROPERTY)
@JsonSubTypes(
@JsonSubTypes.Type(value = Dog.class, name = "Dog"),
@JsonSubTypes.Type(value = Cat.class, name = "Cat")
)
in the above example, we are defining the subclasses and a custom type.
Using a custome deserializer StdDeserializer<T>
Is there any other way to do this please tell me.
java json spring serialization jackson
java json spring serialization jackson
asked Nov 16 '18 at 13:40
MaxExplodeMaxExplode
1,3021219
asked Nov 16 '18 at 13:40
MaxExplodeMaxExplode
1,3021219
asked Nov 16 '18 at 13:40
MaxExplodeMaxExplode
1,3021219
asked Nov 16 '18 at 13:40
MaxExplodeMaxExplode
1,3021219
asked Nov 16 '18 at 13:40
MaxExplodeMaxExplode
1,3021219
1,3021219
add a comment |
add a comment |
1 Answer
1
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oldest
votes
If you can figure out a way to determine the object subtype from the JSON data, you could write a custom TypeId resolver to handle it for you. See Jackson Custom TypeId Resolver.
answered Nov 16 '18 at 22:19
BaldyBaldy
1,8651114
add a comment |
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1 Answer
1
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1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
If you can figure out a way to determine the object subtype from the JSON data, you could write a custom TypeId resolver to handle it for you. See Jackson Custom TypeId Resolver.
answered Nov 16 '18 at 22:19
BaldyBaldy
1,8651114
add a comment |
If you can figure out a way to determine the object subtype from the JSON data, you could write a custom TypeId resolver to handle it for you. See Jackson Custom TypeId Resolver.
answered Nov 16 '18 at 22:19
BaldyBaldy
1,8651114
add a comment |
If you can figure out a way to determine the object subtype from the JSON data, you could write a custom TypeId resolver to handle it for you. See Jackson Custom TypeId Resolver.
answered Nov 16 '18 at 22:19
BaldyBaldy
1,8651114
If you can figure out a way to determine the object subtype from the JSON data, you could write a custom TypeId resolver to handle it for you. See Jackson Custom TypeId Resolver.
answered Nov 16 '18 at 22:19
BaldyBaldy
1,8651114
answered Nov 16 '18 at 22:19
BaldyBaldy
1,8651114
answered Nov 16 '18 at 22:19
BaldyBaldy
1,8651114
answered Nov 16 '18 at 22:19
BaldyBaldy
1,8651114
1,8651114
add a comment |
add a comment |
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