How to push a string in stack?










0














How to push a string in stack,



I have used these structures to develop a stack to store students details and their marks,



 typedef struct node
char name[50];
int marks;
struct node * next;
Node;

typedef struct
int no_student;
Node * top;
stack;


My Push function to push his name and marks into the stack is below,



void Push(stack *S, char name, int marks)
Node *np;
np = (Node*)malloc(sizeof(Node));
np->marks = marks;
strcpy(S->top->name, name);
np->next = S->top;
S->top = np;
S->no_student++;



When I run this code, Compiler giving me a run time error, How can I fix this?










share|improve this question



















  • 2




    sizeof(np) is the size of the pointer np, not the structure it (will) point to. You need to use sizeof *np.
    – Some programmer dude
    Nov 12 at 9:27






  • 1




    There are other problems with your code as well, I suggest you do some rubber duck debugging.
    – Some programmer dude
    Nov 12 at 9:29






  • 1




    This looks more like a linked list than a stack IMHO.
    – babon
    Nov 12 at 9:29






  • 1




    @babon Linked lists are the simplest way of creating a stack without specific limits.
    – Some programmer dude
    Nov 12 at 9:33







  • 1




    strcpy(S->top->name, name); shouldn't be strcpy(np->name, name);? Trying to copy new name on old top of stack will fail at beginning when the stack is empty and S->top==NULL.
    – Frankie_C
    Nov 12 at 9:54
















0














How to push a string in stack,



I have used these structures to develop a stack to store students details and their marks,



 typedef struct node
char name[50];
int marks;
struct node * next;
Node;

typedef struct
int no_student;
Node * top;
stack;


My Push function to push his name and marks into the stack is below,



void Push(stack *S, char name, int marks)
Node *np;
np = (Node*)malloc(sizeof(Node));
np->marks = marks;
strcpy(S->top->name, name);
np->next = S->top;
S->top = np;
S->no_student++;



When I run this code, Compiler giving me a run time error, How can I fix this?










share|improve this question



















  • 2




    sizeof(np) is the size of the pointer np, not the structure it (will) point to. You need to use sizeof *np.
    – Some programmer dude
    Nov 12 at 9:27






  • 1




    There are other problems with your code as well, I suggest you do some rubber duck debugging.
    – Some programmer dude
    Nov 12 at 9:29






  • 1




    This looks more like a linked list than a stack IMHO.
    – babon
    Nov 12 at 9:29






  • 1




    @babon Linked lists are the simplest way of creating a stack without specific limits.
    – Some programmer dude
    Nov 12 at 9:33







  • 1




    strcpy(S->top->name, name); shouldn't be strcpy(np->name, name);? Trying to copy new name on old top of stack will fail at beginning when the stack is empty and S->top==NULL.
    – Frankie_C
    Nov 12 at 9:54














0












0








0







How to push a string in stack,



I have used these structures to develop a stack to store students details and their marks,



 typedef struct node
char name[50];
int marks;
struct node * next;
Node;

typedef struct
int no_student;
Node * top;
stack;


My Push function to push his name and marks into the stack is below,



void Push(stack *S, char name, int marks)
Node *np;
np = (Node*)malloc(sizeof(Node));
np->marks = marks;
strcpy(S->top->name, name);
np->next = S->top;
S->top = np;
S->no_student++;



When I run this code, Compiler giving me a run time error, How can I fix this?










share|improve this question















How to push a string in stack,



I have used these structures to develop a stack to store students details and their marks,



 typedef struct node
char name[50];
int marks;
struct node * next;
Node;

typedef struct
int no_student;
Node * top;
stack;


My Push function to push his name and marks into the stack is below,



void Push(stack *S, char name, int marks)
Node *np;
np = (Node*)malloc(sizeof(Node));
np->marks = marks;
strcpy(S->top->name, name);
np->next = S->top;
S->top = np;
S->no_student++;



When I run this code, Compiler giving me a run time error, How can I fix this?







c string stack push






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 12 at 9:29

























asked Nov 12 at 9:25









AS Mohamed Faheem Anver

229




229







  • 2




    sizeof(np) is the size of the pointer np, not the structure it (will) point to. You need to use sizeof *np.
    – Some programmer dude
    Nov 12 at 9:27






  • 1




    There are other problems with your code as well, I suggest you do some rubber duck debugging.
    – Some programmer dude
    Nov 12 at 9:29






  • 1




    This looks more like a linked list than a stack IMHO.
    – babon
    Nov 12 at 9:29






  • 1




    @babon Linked lists are the simplest way of creating a stack without specific limits.
    – Some programmer dude
    Nov 12 at 9:33







  • 1




    strcpy(S->top->name, name); shouldn't be strcpy(np->name, name);? Trying to copy new name on old top of stack will fail at beginning when the stack is empty and S->top==NULL.
    – Frankie_C
    Nov 12 at 9:54













  • 2




    sizeof(np) is the size of the pointer np, not the structure it (will) point to. You need to use sizeof *np.
    – Some programmer dude
    Nov 12 at 9:27






  • 1




    There are other problems with your code as well, I suggest you do some rubber duck debugging.
    – Some programmer dude
    Nov 12 at 9:29






  • 1




    This looks more like a linked list than a stack IMHO.
    – babon
    Nov 12 at 9:29






  • 1




    @babon Linked lists are the simplest way of creating a stack without specific limits.
    – Some programmer dude
    Nov 12 at 9:33







  • 1




    strcpy(S->top->name, name); shouldn't be strcpy(np->name, name);? Trying to copy new name on old top of stack will fail at beginning when the stack is empty and S->top==NULL.
    – Frankie_C
    Nov 12 at 9:54








2




2




sizeof(np) is the size of the pointer np, not the structure it (will) point to. You need to use sizeof *np.
– Some programmer dude
Nov 12 at 9:27




sizeof(np) is the size of the pointer np, not the structure it (will) point to. You need to use sizeof *np.
– Some programmer dude
Nov 12 at 9:27




1




1




There are other problems with your code as well, I suggest you do some rubber duck debugging.
– Some programmer dude
Nov 12 at 9:29




There are other problems with your code as well, I suggest you do some rubber duck debugging.
– Some programmer dude
Nov 12 at 9:29




1




1




This looks more like a linked list than a stack IMHO.
– babon
Nov 12 at 9:29




This looks more like a linked list than a stack IMHO.
– babon
Nov 12 at 9:29




1




1




@babon Linked lists are the simplest way of creating a stack without specific limits.
– Some programmer dude
Nov 12 at 9:33





@babon Linked lists are the simplest way of creating a stack without specific limits.
– Some programmer dude
Nov 12 at 9:33





1




1




strcpy(S->top->name, name); shouldn't be strcpy(np->name, name);? Trying to copy new name on old top of stack will fail at beginning when the stack is empty and S->top==NULL.
– Frankie_C
Nov 12 at 9:54





strcpy(S->top->name, name); shouldn't be strcpy(np->name, name);? Trying to copy new name on old top of stack will fail at beginning when the stack is empty and S->top==NULL.
– Frankie_C
Nov 12 at 9:54


















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