Can someone please tell me how to read the following: /.(js)$/
I'm trying to understand some webserver code I found online and the part right after the "else if" is the only part I don't understand. (I just started learning this stuff). Thanks
var path = url.parse(req.url).pathname;
// Managing the root route
if (path == '/')
index = fs.readFile(__dirname+'/public/index.html',
function(error,data)
//do stuff...
);
// Managing the route for the javascript files
else if( /.(js)$/.test(path) ) {
index = fs.readFile(__dirname+'/public'+path,
function(error,data)
//do stuff...
);javascript linux command-line
asked Nov 15 '18 at 20:31
CollinACollinA
12
add a comment |
I'm trying to understand some webserver code I found online and the part right after the "else if" is the only part I don't understand. (I just started learning this stuff). Thanks
var path = url.parse(req.url).pathname;
// Managing the root route
if (path == '/')
index = fs.readFile(__dirname+'/public/index.html',
function(error,data)
//do stuff...
);
// Managing the route for the javascript files
else if( /.(js)$/.test(path) ) {
index = fs.readFile(__dirname+'/public'+path,
function(error,data)
//do stuff...
);javascript linux command-line
asked Nov 15 '18 at 20:31
CollinACollinA
12
1
It's a regular expression literal.
– Pointy
Nov 15 '18 at 20:32
Possible duplicate of Learning Regular Expressions
– Sean Pianka
Nov 15 '18 at 20:42
add a comment |
I'm trying to understand some webserver code I found online and the part right after the "else if" is the only part I don't understand. (I just started learning this stuff). Thanks
var path = url.parse(req.url).pathname;
// Managing the root route
if (path == '/')
index = fs.readFile(__dirname+'/public/index.html',
function(error,data)
//do stuff...
);
// Managing the route for the javascript files
else if( /.(js)$/.test(path) ) {
index = fs.readFile(__dirname+'/public'+path,
function(error,data)
//do stuff...
);javascript linux command-line
asked Nov 15 '18 at 20:31
CollinACollinA
12
I'm trying to understand some webserver code I found online and the part right after the "else if" is the only part I don't understand. (I just started learning this stuff). Thanks
var path = url.parse(req.url).pathname;
// Managing the root route
if (path == '/')
index = fs.readFile(__dirname+'/public/index.html',
function(error,data)
//do stuff...
);
// Managing the route for the javascript files
else if( /.(js)$/.test(path) ) {
index = fs.readFile(__dirname+'/public'+path,
function(error,data)
//do stuff...
);var path = url.parse(req.url).pathname;
// Managing the root route
if (path == '/')
index = fs.readFile(__dirname+'/public/index.html',
function(error,data)
//do stuff...
);
// Managing the route for the javascript files
else if( /.(js)$/.test(path) ) {
index = fs.readFile(__dirname+'/public'+path,
function(error,data)
//do stuff...
);var path = url.parse(req.url).pathname;
// Managing the root route
if (path == '/')
index = fs.readFile(__dirname+'/public/index.html',
function(error,data)
//do stuff...
);
// Managing the route for the javascript files
else if( /.(js)$/.test(path) ) {
index = fs.readFile(__dirname+'/public'+path,
function(error,data)
//do stuff...
);javascript linux command-line
javascript linux command-line
asked Nov 15 '18 at 20:31
CollinACollinA
12
asked Nov 15 '18 at 20:31
CollinACollinA
12
asked Nov 15 '18 at 20:31
CollinACollinA
12
asked Nov 15 '18 at 20:31
CollinACollinA
12
asked Nov 15 '18 at 20:31
CollinACollinA
12
12
1
It's a regular expression literal.
– Pointy
Nov 15 '18 at 20:32
Possible duplicate of Learning Regular Expressions
– Sean Pianka
Nov 15 '18 at 20:42
add a comment |
1
It's a regular expression literal.
– Pointy
Nov 15 '18 at 20:32
Possible duplicate of Learning Regular Expressions
– Sean Pianka
Nov 15 '18 at 20:42
1
1
It's a regular expression literal.
– Pointy
Nov 15 '18 at 20:32
It's a regular expression literal.
– Pointy
Nov 15 '18 at 20:32
Possible duplicate of Learning Regular Expressions
– Sean Pianka
Nov 15 '18 at 20:42
Possible duplicate of Learning Regular Expressions
– Sean Pianka
Nov 15 '18 at 20:42
add a comment |
2 Answers
2
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oldest
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It allows you to test against regular expresions.
Heres the MDN on how it works.
In your example, it's checking if the path ends in .js
answered Nov 15 '18 at 20:36
SpeedOfRoundSpeedOfRound
629314
add a comment |
Regular expressions produce non strict match against the string.
Besides MSDN @SpeedOfRound mentioned about it would be useful to play with this service to get the better understanding on your exact case
answered Nov 15 '18 at 23:11
Case TrackerCase Tracker
212
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2 Answers
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active
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2 Answers
2
active
oldest
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active
oldest
votes
active
oldest
votes
It allows you to test against regular expresions.
Heres the MDN on how it works.
In your example, it's checking if the path ends in .js
answered Nov 15 '18 at 20:36
SpeedOfRoundSpeedOfRound
629314
add a comment |
It allows you to test against regular expresions.
Heres the MDN on how it works.
In your example, it's checking if the path ends in .js
answered Nov 15 '18 at 20:36
SpeedOfRoundSpeedOfRound
629314
add a comment |
It allows you to test against regular expresions.
Heres the MDN on how it works.
In your example, it's checking if the path ends in .js
answered Nov 15 '18 at 20:36
SpeedOfRoundSpeedOfRound
629314
It allows you to test against regular expresions.
Heres the MDN on how it works.
In your example, it's checking if the path ends in .js
answered Nov 15 '18 at 20:36
SpeedOfRoundSpeedOfRound
629314
answered Nov 15 '18 at 20:36
SpeedOfRoundSpeedOfRound
629314
answered Nov 15 '18 at 20:36
SpeedOfRoundSpeedOfRound
629314
answered Nov 15 '18 at 20:36
SpeedOfRoundSpeedOfRound
629314
629314
add a comment |
add a comment |
Regular expressions produce non strict match against the string.
Besides MSDN @SpeedOfRound mentioned about it would be useful to play with this service to get the better understanding on your exact case
answered Nov 15 '18 at 23:11
Case TrackerCase Tracker
212
add a comment |
Regular expressions produce non strict match against the string.
Besides MSDN @SpeedOfRound mentioned about it would be useful to play with this service to get the better understanding on your exact case
answered Nov 15 '18 at 23:11
Case TrackerCase Tracker
212
add a comment |
Regular expressions produce non strict match against the string.
Besides MSDN @SpeedOfRound mentioned about it would be useful to play with this service to get the better understanding on your exact case
answered Nov 15 '18 at 23:11
Case TrackerCase Tracker
212
Regular expressions produce non strict match against the string.
Besides MSDN @SpeedOfRound mentioned about it would be useful to play with this service to get the better understanding on your exact case
answered Nov 15 '18 at 23:11
Case TrackerCase Tracker
212
answered Nov 15 '18 at 23:11
Case TrackerCase Tracker
212
answered Nov 15 '18 at 23:11
Case TrackerCase Tracker
212
answered Nov 15 '18 at 23:11
Case TrackerCase Tracker
212
212
add a comment |
add a comment |
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1
It's a regular expression literal.
– Pointy
Nov 15 '18 at 20:32
Possible duplicate of Learning Regular Expressions
– Sean Pianka
Nov 15 '18 at 20:42