Listen for dispatched action in Redux
I'm wondering if there's a way to listen for an action that's been successfully dispatched in redux?
In the ngxs state management library for Angular, I can do the following:
ngOnInit()
this.actions$
.pipe(
ofActionSuccessful(AddedThingToDo),
map((event: AddedThingToDo) => event.thingToDo),
tap(thingToDo => console.log('Action was successfully dispatched'))
)
.subscribe();
Where I can then perform an action when I know that AddedThingToDo
has been successfully dispatched. This could be something like closing a modal, or perhaps dispatching another action.
I'm using ng-redux
for Angular 1.x, however I think the principle should remain the same that it would for react redux.
The only way I've been getting around it is with a callback in my actions, but it feels very wrong:
export const addThingToDo = (model: IThingToDo, onSuccess?: (model: IThingToDo) => void) =>
async (dispatch: Dispatch) =>
dispatch(addingThingToDo());
try
const createdItem = await api.post<IThingToDo>(url, model);
dispatch(addedThingToDo(createdItem));
if (onSuccess)
onSuccess(createdItem);
catch (ex)
dispatch(addThingToDoFailure(ex));
;
javascript redux ngredux
add a comment |
I'm wondering if there's a way to listen for an action that's been successfully dispatched in redux?
In the ngxs state management library for Angular, I can do the following:
ngOnInit()
this.actions$
.pipe(
ofActionSuccessful(AddedThingToDo),
map((event: AddedThingToDo) => event.thingToDo),
tap(thingToDo => console.log('Action was successfully dispatched'))
)
.subscribe();
Where I can then perform an action when I know that AddedThingToDo
has been successfully dispatched. This could be something like closing a modal, or perhaps dispatching another action.
I'm using ng-redux
for Angular 1.x, however I think the principle should remain the same that it would for react redux.
The only way I've been getting around it is with a callback in my actions, but it feels very wrong:
export const addThingToDo = (model: IThingToDo, onSuccess?: (model: IThingToDo) => void) =>
async (dispatch: Dispatch) =>
dispatch(addingThingToDo());
try
const createdItem = await api.post<IThingToDo>(url, model);
dispatch(addedThingToDo(createdItem));
if (onSuccess)
onSuccess(createdItem);
catch (ex)
dispatch(addThingToDoFailure(ex));
;
javascript redux ngredux
add a comment |
I'm wondering if there's a way to listen for an action that's been successfully dispatched in redux?
In the ngxs state management library for Angular, I can do the following:
ngOnInit()
this.actions$
.pipe(
ofActionSuccessful(AddedThingToDo),
map((event: AddedThingToDo) => event.thingToDo),
tap(thingToDo => console.log('Action was successfully dispatched'))
)
.subscribe();
Where I can then perform an action when I know that AddedThingToDo
has been successfully dispatched. This could be something like closing a modal, or perhaps dispatching another action.
I'm using ng-redux
for Angular 1.x, however I think the principle should remain the same that it would for react redux.
The only way I've been getting around it is with a callback in my actions, but it feels very wrong:
export const addThingToDo = (model: IThingToDo, onSuccess?: (model: IThingToDo) => void) =>
async (dispatch: Dispatch) =>
dispatch(addingThingToDo());
try
const createdItem = await api.post<IThingToDo>(url, model);
dispatch(addedThingToDo(createdItem));
if (onSuccess)
onSuccess(createdItem);
catch (ex)
dispatch(addThingToDoFailure(ex));
;
javascript redux ngredux
I'm wondering if there's a way to listen for an action that's been successfully dispatched in redux?
In the ngxs state management library for Angular, I can do the following:
ngOnInit()
this.actions$
.pipe(
ofActionSuccessful(AddedThingToDo),
map((event: AddedThingToDo) => event.thingToDo),
tap(thingToDo => console.log('Action was successfully dispatched'))
)
.subscribe();
Where I can then perform an action when I know that AddedThingToDo
has been successfully dispatched. This could be something like closing a modal, or perhaps dispatching another action.
I'm using ng-redux
for Angular 1.x, however I think the principle should remain the same that it would for react redux.
The only way I've been getting around it is with a callback in my actions, but it feels very wrong:
export const addThingToDo = (model: IThingToDo, onSuccess?: (model: IThingToDo) => void) =>
async (dispatch: Dispatch) =>
dispatch(addingThingToDo());
try
const createdItem = await api.post<IThingToDo>(url, model);
dispatch(addedThingToDo(createdItem));
if (onSuccess)
onSuccess(createdItem);
catch (ex)
dispatch(addThingToDoFailure(ex));
;
javascript redux ngredux
javascript redux ngredux
edited Nov 16 '18 at 9:10
Tom
asked Nov 15 '18 at 16:43
TomTom
1,3071917
1,3071917
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
Turns out redux-thunk
supports returning promises, so I can just return a promise rather than use a callback method.
export const addThingToDo = (model: IThingToDo) =>
async (dispatch: Dispatch): Promise<IThingToDo> =>
await new Promise<IThingToDo>(async (resolve, reject) =>
dispatch(addingThingToDo());
try
const newItem = await api.post<IThingToDo>(url, model);
dispatch(addedThingToDo(newItem));
resolve(newItem);
catch (ex)
dispatch(addThingToDoFailure(ex));
reject(ex);
);
this.addThingToDo(thingToDo)
.then(t => navigateTo(`/things-to-do/$t.id`));
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
Turns out redux-thunk
supports returning promises, so I can just return a promise rather than use a callback method.
export const addThingToDo = (model: IThingToDo) =>
async (dispatch: Dispatch): Promise<IThingToDo> =>
await new Promise<IThingToDo>(async (resolve, reject) =>
dispatch(addingThingToDo());
try
const newItem = await api.post<IThingToDo>(url, model);
dispatch(addedThingToDo(newItem));
resolve(newItem);
catch (ex)
dispatch(addThingToDoFailure(ex));
reject(ex);
);
this.addThingToDo(thingToDo)
.then(t => navigateTo(`/things-to-do/$t.id`));
add a comment |
Turns out redux-thunk
supports returning promises, so I can just return a promise rather than use a callback method.
export const addThingToDo = (model: IThingToDo) =>
async (dispatch: Dispatch): Promise<IThingToDo> =>
await new Promise<IThingToDo>(async (resolve, reject) =>
dispatch(addingThingToDo());
try
const newItem = await api.post<IThingToDo>(url, model);
dispatch(addedThingToDo(newItem));
resolve(newItem);
catch (ex)
dispatch(addThingToDoFailure(ex));
reject(ex);
);
this.addThingToDo(thingToDo)
.then(t => navigateTo(`/things-to-do/$t.id`));
add a comment |
Turns out redux-thunk
supports returning promises, so I can just return a promise rather than use a callback method.
export const addThingToDo = (model: IThingToDo) =>
async (dispatch: Dispatch): Promise<IThingToDo> =>
await new Promise<IThingToDo>(async (resolve, reject) =>
dispatch(addingThingToDo());
try
const newItem = await api.post<IThingToDo>(url, model);
dispatch(addedThingToDo(newItem));
resolve(newItem);
catch (ex)
dispatch(addThingToDoFailure(ex));
reject(ex);
);
this.addThingToDo(thingToDo)
.then(t => navigateTo(`/things-to-do/$t.id`));
Turns out redux-thunk
supports returning promises, so I can just return a promise rather than use a callback method.
export const addThingToDo = (model: IThingToDo) =>
async (dispatch: Dispatch): Promise<IThingToDo> =>
await new Promise<IThingToDo>(async (resolve, reject) =>
dispatch(addingThingToDo());
try
const newItem = await api.post<IThingToDo>(url, model);
dispatch(addedThingToDo(newItem));
resolve(newItem);
catch (ex)
dispatch(addThingToDoFailure(ex));
reject(ex);
);
this.addThingToDo(thingToDo)
.then(t => navigateTo(`/things-to-do/$t.id`));
answered Nov 19 '18 at 10:19
TomTom
1,3071917
1,3071917
add a comment |
add a comment |
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