ordering list of coordinates on row basis










2















I am trying to order a set of coordinates in a specific way



If I have a yet-to-be ordered set of coordinates that represent different cells in some grid,



(2, 2), (3, 1), (1, 2), (3, 2), (1, 3)


My goal is to order this from left to right starting from the bottom row.



schematic of coordinates

0 1 2 3 4
0 X X X X X
1 X X O O X
2 X X O X X
3 X O O X X


(3, 1), (3, 2), (2, 2), (1, 2), (1, 3) # desired output


I came up with the following code, but this would fail in the case where the row number is same but column number is different



data = (1, 2), (1, 4), (2, 2), (0, 3), (0, 4)

data_1 = sorted(data, key=lambda x: x[0], reverse=True)

data_2 = sorted(data_1, key=lambda x: x[1])

>>> print(data_2)
[(2, 2), (1, 2), (0, 3), (1, 4), (0, 4)]

# desired output
[(2, 2), (1, 2), (1, 4), (0, 3), (0, 4)]


What improvement can I make?










share|improve this question




























    2















    I am trying to order a set of coordinates in a specific way



    If I have a yet-to-be ordered set of coordinates that represent different cells in some grid,



    (2, 2), (3, 1), (1, 2), (3, 2), (1, 3)


    My goal is to order this from left to right starting from the bottom row.



    schematic of coordinates

    0 1 2 3 4
    0 X X X X X
    1 X X O O X
    2 X X O X X
    3 X O O X X


    (3, 1), (3, 2), (2, 2), (1, 2), (1, 3) # desired output


    I came up with the following code, but this would fail in the case where the row number is same but column number is different



    data = (1, 2), (1, 4), (2, 2), (0, 3), (0, 4)

    data_1 = sorted(data, key=lambda x: x[0], reverse=True)

    data_2 = sorted(data_1, key=lambda x: x[1])

    >>> print(data_2)
    [(2, 2), (1, 2), (0, 3), (1, 4), (0, 4)]

    # desired output
    [(2, 2), (1, 2), (1, 4), (0, 3), (0, 4)]


    What improvement can I make?










    share|improve this question


























      2












      2








      2








      I am trying to order a set of coordinates in a specific way



      If I have a yet-to-be ordered set of coordinates that represent different cells in some grid,



      (2, 2), (3, 1), (1, 2), (3, 2), (1, 3)


      My goal is to order this from left to right starting from the bottom row.



      schematic of coordinates

      0 1 2 3 4
      0 X X X X X
      1 X X O O X
      2 X X O X X
      3 X O O X X


      (3, 1), (3, 2), (2, 2), (1, 2), (1, 3) # desired output


      I came up with the following code, but this would fail in the case where the row number is same but column number is different



      data = (1, 2), (1, 4), (2, 2), (0, 3), (0, 4)

      data_1 = sorted(data, key=lambda x: x[0], reverse=True)

      data_2 = sorted(data_1, key=lambda x: x[1])

      >>> print(data_2)
      [(2, 2), (1, 2), (0, 3), (1, 4), (0, 4)]

      # desired output
      [(2, 2), (1, 2), (1, 4), (0, 3), (0, 4)]


      What improvement can I make?










      share|improve this question
















      I am trying to order a set of coordinates in a specific way



      If I have a yet-to-be ordered set of coordinates that represent different cells in some grid,



      (2, 2), (3, 1), (1, 2), (3, 2), (1, 3)


      My goal is to order this from left to right starting from the bottom row.



      schematic of coordinates

      0 1 2 3 4
      0 X X X X X
      1 X X O O X
      2 X X O X X
      3 X O O X X


      (3, 1), (3, 2), (2, 2), (1, 2), (1, 3) # desired output


      I came up with the following code, but this would fail in the case where the row number is same but column number is different



      data = (1, 2), (1, 4), (2, 2), (0, 3), (0, 4)

      data_1 = sorted(data, key=lambda x: x[0], reverse=True)

      data_2 = sorted(data_1, key=lambda x: x[1])

      >>> print(data_2)
      [(2, 2), (1, 2), (0, 3), (1, 4), (0, 4)]

      # desired output
      [(2, 2), (1, 2), (1, 4), (0, 3), (0, 4)]


      What improvement can I make?







      python






      share|improve this question















      share|improve this question













      share|improve this question




      share|improve this question








      edited Nov 16 '18 at 5:22









      eyllanesc

      84.4k103562




      84.4k103562










      asked Nov 16 '18 at 5:20









      V AnonV Anon

      2236




      2236






















          2 Answers
          2






          active

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          1














          data = (1, 2), (1, 4), (2, 2), (0, 3), (0, 4)
          sorted(data, key=lambda x:(-x[0],x[1]))
          #[(2, 2), (1, 2), (1, 4), (0, 3), (0, 4)]





          share|improve this answer






























            1

















            def sorted(items):
            for i in range(len(items)-1, 0 , -1):
            for j in range(i):
            if items[j][0] < items[j+1][0]:
            items[j], items[j+1] = items[j+1], items[j]
            continue
            if items[j][0] == items[j+1][0] and items[j][1] > items[j+1][1]:
            items[j], items[j+1] = items[j+1], items[j]
            return items


            data = [(1, 2), (1, 4), (2, 2), (0, 3), (0, 4)]
            print(sorted(data))








            share|improve this answer






















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              2 Answers
              2






              active

              oldest

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              2 Answers
              2






              active

              oldest

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              active

              oldest

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              active

              oldest

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              1














              data = (1, 2), (1, 4), (2, 2), (0, 3), (0, 4)
              sorted(data, key=lambda x:(-x[0],x[1]))
              #[(2, 2), (1, 2), (1, 4), (0, 3), (0, 4)]





              share|improve this answer



























                1














                data = (1, 2), (1, 4), (2, 2), (0, 3), (0, 4)
                sorted(data, key=lambda x:(-x[0],x[1]))
                #[(2, 2), (1, 2), (1, 4), (0, 3), (0, 4)]





                share|improve this answer

























                  1












                  1








                  1







                  data = (1, 2), (1, 4), (2, 2), (0, 3), (0, 4)
                  sorted(data, key=lambda x:(-x[0],x[1]))
                  #[(2, 2), (1, 2), (1, 4), (0, 3), (0, 4)]





                  share|improve this answer













                  data = (1, 2), (1, 4), (2, 2), (0, 3), (0, 4)
                  sorted(data, key=lambda x:(-x[0],x[1]))
                  #[(2, 2), (1, 2), (1, 4), (0, 3), (0, 4)]






                  share|improve this answer












                  share|improve this answer



                  share|improve this answer










                  answered Nov 16 '18 at 5:38









                  TranshumanTranshuman

                  2,7861412




                  2,7861412























                      1

















                      def sorted(items):
                      for i in range(len(items)-1, 0 , -1):
                      for j in range(i):
                      if items[j][0] < items[j+1][0]:
                      items[j], items[j+1] = items[j+1], items[j]
                      continue
                      if items[j][0] == items[j+1][0] and items[j][1] > items[j+1][1]:
                      items[j], items[j+1] = items[j+1], items[j]
                      return items


                      data = [(1, 2), (1, 4), (2, 2), (0, 3), (0, 4)]
                      print(sorted(data))








                      share|improve this answer



























                        1

















                        def sorted(items):
                        for i in range(len(items)-1, 0 , -1):
                        for j in range(i):
                        if items[j][0] < items[j+1][0]:
                        items[j], items[j+1] = items[j+1], items[j]
                        continue
                        if items[j][0] == items[j+1][0] and items[j][1] > items[j+1][1]:
                        items[j], items[j+1] = items[j+1], items[j]
                        return items


                        data = [(1, 2), (1, 4), (2, 2), (0, 3), (0, 4)]
                        print(sorted(data))








                        share|improve this answer

























                          1












                          1








                          1










                          def sorted(items):
                          for i in range(len(items)-1, 0 , -1):
                          for j in range(i):
                          if items[j][0] < items[j+1][0]:
                          items[j], items[j+1] = items[j+1], items[j]
                          continue
                          if items[j][0] == items[j+1][0] and items[j][1] > items[j+1][1]:
                          items[j], items[j+1] = items[j+1], items[j]
                          return items


                          data = [(1, 2), (1, 4), (2, 2), (0, 3), (0, 4)]
                          print(sorted(data))








                          share|improve this answer
















                          def sorted(items):
                          for i in range(len(items)-1, 0 , -1):
                          for j in range(i):
                          if items[j][0] < items[j+1][0]:
                          items[j], items[j+1] = items[j+1], items[j]
                          continue
                          if items[j][0] == items[j+1][0] and items[j][1] > items[j+1][1]:
                          items[j], items[j+1] = items[j+1], items[j]
                          return items


                          data = [(1, 2), (1, 4), (2, 2), (0, 3), (0, 4)]
                          print(sorted(data))








                          def sorted(items):
                          for i in range(len(items)-1, 0 , -1):
                          for j in range(i):
                          if items[j][0] < items[j+1][0]:
                          items[j], items[j+1] = items[j+1], items[j]
                          continue
                          if items[j][0] == items[j+1][0] and items[j][1] > items[j+1][1]:
                          items[j], items[j+1] = items[j+1], items[j]
                          return items


                          data = [(1, 2), (1, 4), (2, 2), (0, 3), (0, 4)]
                          print(sorted(data))





                          def sorted(items):
                          for i in range(len(items)-1, 0 , -1):
                          for j in range(i):
                          if items[j][0] < items[j+1][0]:
                          items[j], items[j+1] = items[j+1], items[j]
                          continue
                          if items[j][0] == items[j+1][0] and items[j][1] > items[j+1][1]:
                          items[j], items[j+1] = items[j+1], items[j]
                          return items


                          data = [(1, 2), (1, 4), (2, 2), (0, 3), (0, 4)]
                          print(sorted(data))






                          share|improve this answer












                          share|improve this answer



                          share|improve this answer










                          answered Nov 16 '18 at 5:46









                          任智文任智文

                          111




                          111



























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