ordering list of coordinates on row basis
I am trying to order a set of coordinates in a specific way
If I have a yet-to-be ordered set of coordinates that represent different cells in some grid,
(2, 2), (3, 1), (1, 2), (3, 2), (1, 3)
My goal is to order this from left to right starting from the bottom row.
schematic of coordinates
0 1 2 3 4
0 X X X X X
1 X X O O X
2 X X O X X
3 X O O X X
(3, 1), (3, 2), (2, 2), (1, 2), (1, 3) # desired output
I came up with the following code, but this would fail in the case where the row number is same but column number is different
data = (1, 2), (1, 4), (2, 2), (0, 3), (0, 4)
data_1 = sorted(data, key=lambda x: x[0], reverse=True)
data_2 = sorted(data_1, key=lambda x: x[1])
>>> print(data_2)
[(2, 2), (1, 2), (0, 3), (1, 4), (0, 4)]
# desired output
[(2, 2), (1, 2), (1, 4), (0, 3), (0, 4)]
What improvement can I make?
python
add a comment |
I am trying to order a set of coordinates in a specific way
If I have a yet-to-be ordered set of coordinates that represent different cells in some grid,
(2, 2), (3, 1), (1, 2), (3, 2), (1, 3)
My goal is to order this from left to right starting from the bottom row.
schematic of coordinates
0 1 2 3 4
0 X X X X X
1 X X O O X
2 X X O X X
3 X O O X X
(3, 1), (3, 2), (2, 2), (1, 2), (1, 3) # desired output
I came up with the following code, but this would fail in the case where the row number is same but column number is different
data = (1, 2), (1, 4), (2, 2), (0, 3), (0, 4)
data_1 = sorted(data, key=lambda x: x[0], reverse=True)
data_2 = sorted(data_1, key=lambda x: x[1])
>>> print(data_2)
[(2, 2), (1, 2), (0, 3), (1, 4), (0, 4)]
# desired output
[(2, 2), (1, 2), (1, 4), (0, 3), (0, 4)]
What improvement can I make?
python
add a comment |
I am trying to order a set of coordinates in a specific way
If I have a yet-to-be ordered set of coordinates that represent different cells in some grid,
(2, 2), (3, 1), (1, 2), (3, 2), (1, 3)
My goal is to order this from left to right starting from the bottom row.
schematic of coordinates
0 1 2 3 4
0 X X X X X
1 X X O O X
2 X X O X X
3 X O O X X
(3, 1), (3, 2), (2, 2), (1, 2), (1, 3) # desired output
I came up with the following code, but this would fail in the case where the row number is same but column number is different
data = (1, 2), (1, 4), (2, 2), (0, 3), (0, 4)
data_1 = sorted(data, key=lambda x: x[0], reverse=True)
data_2 = sorted(data_1, key=lambda x: x[1])
>>> print(data_2)
[(2, 2), (1, 2), (0, 3), (1, 4), (0, 4)]
# desired output
[(2, 2), (1, 2), (1, 4), (0, 3), (0, 4)]
What improvement can I make?
python
I am trying to order a set of coordinates in a specific way
If I have a yet-to-be ordered set of coordinates that represent different cells in some grid,
(2, 2), (3, 1), (1, 2), (3, 2), (1, 3)
My goal is to order this from left to right starting from the bottom row.
schematic of coordinates
0 1 2 3 4
0 X X X X X
1 X X O O X
2 X X O X X
3 X O O X X
(3, 1), (3, 2), (2, 2), (1, 2), (1, 3) # desired output
I came up with the following code, but this would fail in the case where the row number is same but column number is different
data = (1, 2), (1, 4), (2, 2), (0, 3), (0, 4)
data_1 = sorted(data, key=lambda x: x[0], reverse=True)
data_2 = sorted(data_1, key=lambda x: x[1])
>>> print(data_2)
[(2, 2), (1, 2), (0, 3), (1, 4), (0, 4)]
# desired output
[(2, 2), (1, 2), (1, 4), (0, 3), (0, 4)]
What improvement can I make?
python
python
edited Nov 16 '18 at 5:22
eyllanesc
84.4k103562
84.4k103562
asked Nov 16 '18 at 5:20
V AnonV Anon
2236
2236
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add a comment |
2 Answers
2
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oldest
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data = (1, 2), (1, 4), (2, 2), (0, 3), (0, 4)
sorted(data, key=lambda x:(-x[0],x[1]))
#[(2, 2), (1, 2), (1, 4), (0, 3), (0, 4)]
add a comment |
def sorted(items):
for i in range(len(items)-1, 0 , -1):
for j in range(i):
if items[j][0] < items[j+1][0]:
items[j], items[j+1] = items[j+1], items[j]
continue
if items[j][0] == items[j+1][0] and items[j][1] > items[j+1][1]:
items[j], items[j+1] = items[j+1], items[j]
return items
data = [(1, 2), (1, 4), (2, 2), (0, 3), (0, 4)]
print(sorted(data))
add a comment |
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2 Answers
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2 Answers
2
active
oldest
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active
oldest
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active
oldest
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data = (1, 2), (1, 4), (2, 2), (0, 3), (0, 4)
sorted(data, key=lambda x:(-x[0],x[1]))
#[(2, 2), (1, 2), (1, 4), (0, 3), (0, 4)]
add a comment |
data = (1, 2), (1, 4), (2, 2), (0, 3), (0, 4)
sorted(data, key=lambda x:(-x[0],x[1]))
#[(2, 2), (1, 2), (1, 4), (0, 3), (0, 4)]
add a comment |
data = (1, 2), (1, 4), (2, 2), (0, 3), (0, 4)
sorted(data, key=lambda x:(-x[0],x[1]))
#[(2, 2), (1, 2), (1, 4), (0, 3), (0, 4)]
data = (1, 2), (1, 4), (2, 2), (0, 3), (0, 4)
sorted(data, key=lambda x:(-x[0],x[1]))
#[(2, 2), (1, 2), (1, 4), (0, 3), (0, 4)]
answered Nov 16 '18 at 5:38
TranshumanTranshuman
2,7861412
2,7861412
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def sorted(items):
for i in range(len(items)-1, 0 , -1):
for j in range(i):
if items[j][0] < items[j+1][0]:
items[j], items[j+1] = items[j+1], items[j]
continue
if items[j][0] == items[j+1][0] and items[j][1] > items[j+1][1]:
items[j], items[j+1] = items[j+1], items[j]
return items
data = [(1, 2), (1, 4), (2, 2), (0, 3), (0, 4)]
print(sorted(data))
add a comment |
def sorted(items):
for i in range(len(items)-1, 0 , -1):
for j in range(i):
if items[j][0] < items[j+1][0]:
items[j], items[j+1] = items[j+1], items[j]
continue
if items[j][0] == items[j+1][0] and items[j][1] > items[j+1][1]:
items[j], items[j+1] = items[j+1], items[j]
return items
data = [(1, 2), (1, 4), (2, 2), (0, 3), (0, 4)]
print(sorted(data))
add a comment |
def sorted(items):
for i in range(len(items)-1, 0 , -1):
for j in range(i):
if items[j][0] < items[j+1][0]:
items[j], items[j+1] = items[j+1], items[j]
continue
if items[j][0] == items[j+1][0] and items[j][1] > items[j+1][1]:
items[j], items[j+1] = items[j+1], items[j]
return items
data = [(1, 2), (1, 4), (2, 2), (0, 3), (0, 4)]
print(sorted(data))
def sorted(items):
for i in range(len(items)-1, 0 , -1):
for j in range(i):
if items[j][0] < items[j+1][0]:
items[j], items[j+1] = items[j+1], items[j]
continue
if items[j][0] == items[j+1][0] and items[j][1] > items[j+1][1]:
items[j], items[j+1] = items[j+1], items[j]
return items
data = [(1, 2), (1, 4), (2, 2), (0, 3), (0, 4)]
print(sorted(data))
def sorted(items):
for i in range(len(items)-1, 0 , -1):
for j in range(i):
if items[j][0] < items[j+1][0]:
items[j], items[j+1] = items[j+1], items[j]
continue
if items[j][0] == items[j+1][0] and items[j][1] > items[j+1][1]:
items[j], items[j+1] = items[j+1], items[j]
return items
data = [(1, 2), (1, 4), (2, 2), (0, 3), (0, 4)]
print(sorted(data))
def sorted(items):
for i in range(len(items)-1, 0 , -1):
for j in range(i):
if items[j][0] < items[j+1][0]:
items[j], items[j+1] = items[j+1], items[j]
continue
if items[j][0] == items[j+1][0] and items[j][1] > items[j+1][1]:
items[j], items[j+1] = items[j+1], items[j]
return items
data = [(1, 2), (1, 4), (2, 2), (0, 3), (0, 4)]
print(sorted(data))
answered Nov 16 '18 at 5:46
任智文任智文
111
111
add a comment |
add a comment |
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