Return average number of turns over 1000 times










1














I'm relatively new to R and I've been set a project to simulate a game. I've designed the game and entered a code in which it will return the number of turns taken to win the game, however I'm stuck with how to simulate the game 1000 times and return the average, although it seems so simple, I just can't work it out.



The code to return how many turns it takes to win:



 s=seq(1:25)
current=vector()
current[1]=1
gameon=1
turns=1
while(gameon==1)

current[turns+1]=sample(s,1,replace=TRUE,prob=w[current[turns],])
turns=turns+1
if (current[turns]==25)

gameon=0




The game code and transition matrix:



w = matrix(0, nrow=25, ncol=25)
for (i in 1:25) #RED - 1,2 down 2 3,4 back 3 5,6
stay
#AMBER - 1,2 down 1 3,4 back 2 5,6
forward 1
if (i == 4) #GREEN - 1,2 stay 3,4 forward 1 5,6
forward 2

w[i, i+2] = 1/3
w[i,i+1] = 1/3 # effects on a state with a GREEN pub
w[i,i] = 1/3

else if (i == 6)

w[i,i] = 1/3
w[i,i+1] = 1/3
w[i,i+2] = 1/3

else if (i == 7)

w[i,i-3] = 1/3
w[i,i-2] = 1/3 # effects on a state with an AMBER pub
w[i,i+1] = 1/3

else if (i == 12)

w[i,i] = 1/3
w[i,i+1] = 1/3
w[i,i+2] = 1/3

else if (i == 16)

w[i,i-3] = 1/3
w[i,i-2] = 1/3 # effects on a state with a RED pub
w[i,i+1] = 1/3

else if (i == 15)

w[i,i-10] = 1/3
w[i,i-3] = 1/3 # effects on a state with a RED pub
w[i,i] = 1/3

else if (i == 18)

w[i,i] = 1/3
w[i,i+1] = 1/3 # effects on a state with a RED pub
w[i,i+2] = 1/3

else if (i == 21)

w[i,i-10] = 1/3
w[i,i-3] = 1/3
w[i,i] = 1/3

else if (i == 24)

w[i,i-10] = 1/3
w[i,i-3] = 1/3 #horrible square to be stuck on, cant win from
this square.
w[i,i] = 1/3

else if (i <= 19)

w[i, seq(i+1,i+6)] = 1/6

else if (i==20)

w[i,seq(i+1,i+4)] = 1/6
w[i,i+5] = 2/6

else if (i==22)

w[i,seq(i+1,i+2)] = 1/6
w[i,i+3] = 4/6

else if (i == 23)

w[i,i+1] = 1/6
w[i,i+2] = 5/6

else if (i == 25)

w[i,i] = 1 #game finished





I believe a for loop would be best to use but I don't know how to set it up to return the average number of turns.










share|improve this question




























    1














    I'm relatively new to R and I've been set a project to simulate a game. I've designed the game and entered a code in which it will return the number of turns taken to win the game, however I'm stuck with how to simulate the game 1000 times and return the average, although it seems so simple, I just can't work it out.



    The code to return how many turns it takes to win:



     s=seq(1:25)
    current=vector()
    current[1]=1
    gameon=1
    turns=1
    while(gameon==1)

    current[turns+1]=sample(s,1,replace=TRUE,prob=w[current[turns],])
    turns=turns+1
    if (current[turns]==25)

    gameon=0




    The game code and transition matrix:



    w = matrix(0, nrow=25, ncol=25)
    for (i in 1:25) #RED - 1,2 down 2 3,4 back 3 5,6
    stay
    #AMBER - 1,2 down 1 3,4 back 2 5,6
    forward 1
    if (i == 4) #GREEN - 1,2 stay 3,4 forward 1 5,6
    forward 2

    w[i, i+2] = 1/3
    w[i,i+1] = 1/3 # effects on a state with a GREEN pub
    w[i,i] = 1/3

    else if (i == 6)

    w[i,i] = 1/3
    w[i,i+1] = 1/3
    w[i,i+2] = 1/3

    else if (i == 7)

    w[i,i-3] = 1/3
    w[i,i-2] = 1/3 # effects on a state with an AMBER pub
    w[i,i+1] = 1/3

    else if (i == 12)

    w[i,i] = 1/3
    w[i,i+1] = 1/3
    w[i,i+2] = 1/3

    else if (i == 16)

    w[i,i-3] = 1/3
    w[i,i-2] = 1/3 # effects on a state with a RED pub
    w[i,i+1] = 1/3

    else if (i == 15)

    w[i,i-10] = 1/3
    w[i,i-3] = 1/3 # effects on a state with a RED pub
    w[i,i] = 1/3

    else if (i == 18)

    w[i,i] = 1/3
    w[i,i+1] = 1/3 # effects on a state with a RED pub
    w[i,i+2] = 1/3

    else if (i == 21)

    w[i,i-10] = 1/3
    w[i,i-3] = 1/3
    w[i,i] = 1/3

    else if (i == 24)

    w[i,i-10] = 1/3
    w[i,i-3] = 1/3 #horrible square to be stuck on, cant win from
    this square.
    w[i,i] = 1/3

    else if (i <= 19)

    w[i, seq(i+1,i+6)] = 1/6

    else if (i==20)

    w[i,seq(i+1,i+4)] = 1/6
    w[i,i+5] = 2/6

    else if (i==22)

    w[i,seq(i+1,i+2)] = 1/6
    w[i,i+3] = 4/6

    else if (i == 23)

    w[i,i+1] = 1/6
    w[i,i+2] = 5/6

    else if (i == 25)

    w[i,i] = 1 #game finished





    I believe a for loop would be best to use but I don't know how to set it up to return the average number of turns.










    share|improve this question


























      1












      1








      1







      I'm relatively new to R and I've been set a project to simulate a game. I've designed the game and entered a code in which it will return the number of turns taken to win the game, however I'm stuck with how to simulate the game 1000 times and return the average, although it seems so simple, I just can't work it out.



      The code to return how many turns it takes to win:



       s=seq(1:25)
      current=vector()
      current[1]=1
      gameon=1
      turns=1
      while(gameon==1)

      current[turns+1]=sample(s,1,replace=TRUE,prob=w[current[turns],])
      turns=turns+1
      if (current[turns]==25)

      gameon=0




      The game code and transition matrix:



      w = matrix(0, nrow=25, ncol=25)
      for (i in 1:25) #RED - 1,2 down 2 3,4 back 3 5,6
      stay
      #AMBER - 1,2 down 1 3,4 back 2 5,6
      forward 1
      if (i == 4) #GREEN - 1,2 stay 3,4 forward 1 5,6
      forward 2

      w[i, i+2] = 1/3
      w[i,i+1] = 1/3 # effects on a state with a GREEN pub
      w[i,i] = 1/3

      else if (i == 6)

      w[i,i] = 1/3
      w[i,i+1] = 1/3
      w[i,i+2] = 1/3

      else if (i == 7)

      w[i,i-3] = 1/3
      w[i,i-2] = 1/3 # effects on a state with an AMBER pub
      w[i,i+1] = 1/3

      else if (i == 12)

      w[i,i] = 1/3
      w[i,i+1] = 1/3
      w[i,i+2] = 1/3

      else if (i == 16)

      w[i,i-3] = 1/3
      w[i,i-2] = 1/3 # effects on a state with a RED pub
      w[i,i+1] = 1/3

      else if (i == 15)

      w[i,i-10] = 1/3
      w[i,i-3] = 1/3 # effects on a state with a RED pub
      w[i,i] = 1/3

      else if (i == 18)

      w[i,i] = 1/3
      w[i,i+1] = 1/3 # effects on a state with a RED pub
      w[i,i+2] = 1/3

      else if (i == 21)

      w[i,i-10] = 1/3
      w[i,i-3] = 1/3
      w[i,i] = 1/3

      else if (i == 24)

      w[i,i-10] = 1/3
      w[i,i-3] = 1/3 #horrible square to be stuck on, cant win from
      this square.
      w[i,i] = 1/3

      else if (i <= 19)

      w[i, seq(i+1,i+6)] = 1/6

      else if (i==20)

      w[i,seq(i+1,i+4)] = 1/6
      w[i,i+5] = 2/6

      else if (i==22)

      w[i,seq(i+1,i+2)] = 1/6
      w[i,i+3] = 4/6

      else if (i == 23)

      w[i,i+1] = 1/6
      w[i,i+2] = 5/6

      else if (i == 25)

      w[i,i] = 1 #game finished





      I believe a for loop would be best to use but I don't know how to set it up to return the average number of turns.










      share|improve this question















      I'm relatively new to R and I've been set a project to simulate a game. I've designed the game and entered a code in which it will return the number of turns taken to win the game, however I'm stuck with how to simulate the game 1000 times and return the average, although it seems so simple, I just can't work it out.



      The code to return how many turns it takes to win:



       s=seq(1:25)
      current=vector()
      current[1]=1
      gameon=1
      turns=1
      while(gameon==1)

      current[turns+1]=sample(s,1,replace=TRUE,prob=w[current[turns],])
      turns=turns+1
      if (current[turns]==25)

      gameon=0




      The game code and transition matrix:



      w = matrix(0, nrow=25, ncol=25)
      for (i in 1:25) #RED - 1,2 down 2 3,4 back 3 5,6
      stay
      #AMBER - 1,2 down 1 3,4 back 2 5,6
      forward 1
      if (i == 4) #GREEN - 1,2 stay 3,4 forward 1 5,6
      forward 2

      w[i, i+2] = 1/3
      w[i,i+1] = 1/3 # effects on a state with a GREEN pub
      w[i,i] = 1/3

      else if (i == 6)

      w[i,i] = 1/3
      w[i,i+1] = 1/3
      w[i,i+2] = 1/3

      else if (i == 7)

      w[i,i-3] = 1/3
      w[i,i-2] = 1/3 # effects on a state with an AMBER pub
      w[i,i+1] = 1/3

      else if (i == 12)

      w[i,i] = 1/3
      w[i,i+1] = 1/3
      w[i,i+2] = 1/3

      else if (i == 16)

      w[i,i-3] = 1/3
      w[i,i-2] = 1/3 # effects on a state with a RED pub
      w[i,i+1] = 1/3

      else if (i == 15)

      w[i,i-10] = 1/3
      w[i,i-3] = 1/3 # effects on a state with a RED pub
      w[i,i] = 1/3

      else if (i == 18)

      w[i,i] = 1/3
      w[i,i+1] = 1/3 # effects on a state with a RED pub
      w[i,i+2] = 1/3

      else if (i == 21)

      w[i,i-10] = 1/3
      w[i,i-3] = 1/3
      w[i,i] = 1/3

      else if (i == 24)

      w[i,i-10] = 1/3
      w[i,i-3] = 1/3 #horrible square to be stuck on, cant win from
      this square.
      w[i,i] = 1/3

      else if (i <= 19)

      w[i, seq(i+1,i+6)] = 1/6

      else if (i==20)

      w[i,seq(i+1,i+4)] = 1/6
      w[i,i+5] = 2/6

      else if (i==22)

      w[i,seq(i+1,i+2)] = 1/6
      w[i,i+3] = 4/6

      else if (i == 23)

      w[i,i+1] = 1/6
      w[i,i+2] = 5/6

      else if (i == 25)

      w[i,i] = 1 #game finished





      I believe a for loop would be best to use but I don't know how to set it up to return the average number of turns.







      r for-loop simulation markov-chains






      share|improve this question















      share|improve this question













      share|improve this question




      share|improve this question








      edited Nov 12 at 20:19









      benvc

      3,7671319




      3,7671319










      asked Nov 12 at 19:35









      F. Wotton

      254




      254



























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