dictionary key type confusion isinstance python [duplicate]

This question already has an answer here:

What are the differences between type() and isinstance()?

6 answers

I can't understand following execution. I expected different results.

>>> f = 'ms':'ma'
>>> isinstance(f['ms'], type(str))
False

>>> isinstance(f['ms'], type(dict))
False

>>> type(f['ms'])
<class 'str'>

edited Nov 15 '18 at 12:09

asked Nov 15 '18 at 11:40

waltexwq

103

marked as duplicate by MisterMiyagi, jpp dictionary
Users with the dictionary badge can single-handedly close dictionary questions as duplicates and reopen them as needed.

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Nov 15 '18 at 11:54

This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.

5

type(str) returns type, so you are checking if f['ms'] is an instance of type, not an instance of str. If you want to check if something is a string, use isinstance(f['ms'], str).

– khelwood
Nov 15 '18 at 11:42

add a comment |

This question already has an answer here:

What are the differences between type() and isinstance()?

6 answers

I can't understand following execution. I expected different results.

>>> f = 'ms':'ma'
>>> isinstance(f['ms'], type(str))
False

>>> isinstance(f['ms'], type(dict))
False

>>> type(f['ms'])
<class 'str'>

edited Nov 15 '18 at 12:09

asked Nov 15 '18 at 11:40

waltexwq

103

marked as duplicate by MisterMiyagi, jpp dictionary
Users with the dictionary badge can single-handedly close dictionary questions as duplicates and reopen them as needed.

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Nov 15 '18 at 11:54

This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.

5

type(str) returns type, so you are checking if f['ms'] is an instance of type, not an instance of str. If you want to check if something is a string, use isinstance(f['ms'], str).

– khelwood
Nov 15 '18 at 11:42

add a comment |

This question already has an answer here:

What are the differences between type() and isinstance()?

6 answers

I can't understand following execution. I expected different results.

>>> f = 'ms':'ma'
>>> isinstance(f['ms'], type(str))
False

>>> isinstance(f['ms'], type(dict))
False

>>> type(f['ms'])
<class 'str'>

edited Nov 15 '18 at 12:09

asked Nov 15 '18 at 11:40

waltexwq

103

This question already has an answer here:

What are the differences between type() and isinstance()?

6 answers

I can't understand following execution. I expected different results.

>>> f = 'ms':'ma'
>>> isinstance(f['ms'], type(str))
False

>>> isinstance(f['ms'], type(dict))
False

>>> type(f['ms'])
<class 'str'>

This question already has an answer here:

What are the differences between type() and isinstance()?

6 answers

python dictionary

edited Nov 15 '18 at 12:09

asked Nov 15 '18 at 11:40

waltexwq

103

edited Nov 15 '18 at 12:09

asked Nov 15 '18 at 11:40

waltexwq

103

edited Nov 15 '18 at 12:09

asked Nov 15 '18 at 11:40

waltexwq

103

asked Nov 15 '18 at 11:40

waltexwq

103

asked Nov 15 '18 at 11:40

waltexwq

103

marked as duplicate by MisterMiyagi, jpp dictionary
Users with the dictionary badge can single-handedly close dictionary questions as duplicates and reopen them as needed.

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Nov 15 '18 at 11:54

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Nov 15 '18 at 11:54

This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.

5

type(str) returns type, so you are checking if f['ms'] is an instance of type, not an instance of str. If you want to check if something is a string, use isinstance(f['ms'], str).

– khelwood
Nov 15 '18 at 11:42

add a comment |

5

type(str) returns type, so you are checking if f['ms'] is an instance of type, not an instance of str. If you want to check if something is a string, use isinstance(f['ms'], str).

– khelwood
Nov 15 '18 at 11:42

type(str) returns type, so you are checking if f['ms'] is an instance of type, not an instance of str. If you want to check if something is a string, use isinstance(f['ms'], str).

– khelwood
Nov 15 '18 at 11:42

add a comment |

2 Answers
2

active

oldest

votes

type(str) and type(dict) each return type, so you are checking if your objects are instances of type, which they are not.

If you want to check if something is a string, use

isinstance(f['ms'], str)

not

isinstance(f['ms'], type(str))

And if you want to test if something is a dict, you can use

isinstance(f['ms'], dict)

not

isinstance(f['ms'], type(dict))

edited Nov 15 '18 at 12:50

answered Nov 15 '18 at 11:46

khelwood

31.5k74364

add a comment |

I think you just want this:

>>> f = 'ms':'ma'
>>> isinstance(f['ms'], str)
True

You don't need type(str)

answered Nov 15 '18 at 11:42

richflow

913211

add a comment |

2 Answers
2

active

oldest

votes

2 Answers
2

active

oldest

votes

type(str) and type(dict) each return type, so you are checking if your objects are instances of type, which they are not.

If you want to check if something is a string, use

isinstance(f['ms'], str)

not

isinstance(f['ms'], type(str))

And if you want to test if something is a dict, you can use

isinstance(f['ms'], dict)

not

isinstance(f['ms'], type(dict))

edited Nov 15 '18 at 12:50

answered Nov 15 '18 at 11:46

khelwood

31.5k74364

add a comment |

type(str) and type(dict) each return type, so you are checking if your objects are instances of type, which they are not.

If you want to check if something is a string, use

isinstance(f['ms'], str)

not

isinstance(f['ms'], type(str))

And if you want to test if something is a dict, you can use

isinstance(f['ms'], dict)

not

isinstance(f['ms'], type(dict))

edited Nov 15 '18 at 12:50

answered Nov 15 '18 at 11:46

khelwood

31.5k74364

add a comment |

type(str) and type(dict) each return type, so you are checking if your objects are instances of type, which they are not.

If you want to check if something is a string, use

isinstance(f['ms'], str)

not

isinstance(f['ms'], type(str))

And if you want to test if something is a dict, you can use

isinstance(f['ms'], dict)

not

isinstance(f['ms'], type(dict))

edited Nov 15 '18 at 12:50

answered Nov 15 '18 at 11:46

khelwood

31.5k74364

type(str) and type(dict) each return type, so you are checking if your objects are instances of type, which they are not.

If you want to check if something is a string, use

isinstance(f['ms'], str)

not

isinstance(f['ms'], type(str))

And if you want to test if something is a dict, you can use

isinstance(f['ms'], dict)

not

isinstance(f['ms'], type(dict))

edited Nov 15 '18 at 12:50

answered Nov 15 '18 at 11:46

khelwood

31.5k74364

edited Nov 15 '18 at 12:50

answered Nov 15 '18 at 11:46

khelwood

31.5k74364

answered Nov 15 '18 at 11:46

khelwood

31.5k74364

answered Nov 15 '18 at 11:46

khelwood

31.5k74364

add a comment |

I think you just want this:

>>> f = 'ms':'ma'
>>> isinstance(f['ms'], str)
True

You don't need type(str)

answered Nov 15 '18 at 11:42

richflow

913211

add a comment |

I think you just want this:

>>> f = 'ms':'ma'
>>> isinstance(f['ms'], str)
True

You don't need type(str)

answered Nov 15 '18 at 11:42

richflow

913211

add a comment |

I think you just want this:

>>> f = 'ms':'ma'
>>> isinstance(f['ms'], str)
True

You don't need type(str)

answered Nov 15 '18 at 11:42

richflow

913211

I think you just want this:

>>> f = 'ms':'ma'
>>> isinstance(f['ms'], str)
True

You don't need type(str)

answered Nov 15 '18 at 11:42

richflow

913211

answered Nov 15 '18 at 11:42

richflow

913211

answered Nov 15 '18 at 11:42

richflow

913211

answered Nov 15 '18 at 11:42

richflow

913211

add a comment |

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