filtering a list of lists of dates in python










2















I have the following list of list:



[[Timestamp('2018-04-07 00:00:00'), Timestamp('2018-07-07 00:00:00'),Timestamp('2020-04-07 00:00:00')], [Timestamp('2018-04-07 00:00:00'),Timestamp('2018-10-07 00:00:00'),Timestamp('2018-12-07 00:00:00'),Timestamp('2021-04-07 00:00:00'),Timestamp('2022-04-07 00:00:00'),Timestamp('2023-04-07 00:00:00')]


And my question is if it is possible filter the list of lists by another date. For example:
If I choose this date:



datetime.datetime(2019, 1, 26, 0, 0)


Is there a way to filter the list of lists to just taking those dates that are higher than the date I choose and also the last one before my date?
For example for the first list of the lists I want to keep the values:



[Timestamp('2018-07-07 00:00:00'),Timestamp('2020-04-07 00:00:00')]


And for the second list of the list of lists:



[Timestamp('2018-12-07 00:00:00'),Timestamp('2021-04-07 00:00:00'),Timestamp('2022-04-07 00:00:00'),Timestamp('2023-04-07 00:00:00')] 









share|improve this question


























    2















    I have the following list of list:



    [[Timestamp('2018-04-07 00:00:00'), Timestamp('2018-07-07 00:00:00'),Timestamp('2020-04-07 00:00:00')], [Timestamp('2018-04-07 00:00:00'),Timestamp('2018-10-07 00:00:00'),Timestamp('2018-12-07 00:00:00'),Timestamp('2021-04-07 00:00:00'),Timestamp('2022-04-07 00:00:00'),Timestamp('2023-04-07 00:00:00')]


    And my question is if it is possible filter the list of lists by another date. For example:
    If I choose this date:



    datetime.datetime(2019, 1, 26, 0, 0)


    Is there a way to filter the list of lists to just taking those dates that are higher than the date I choose and also the last one before my date?
    For example for the first list of the lists I want to keep the values:



    [Timestamp('2018-07-07 00:00:00'),Timestamp('2020-04-07 00:00:00')]


    And for the second list of the list of lists:



    [Timestamp('2018-12-07 00:00:00'),Timestamp('2021-04-07 00:00:00'),Timestamp('2022-04-07 00:00:00'),Timestamp('2023-04-07 00:00:00')] 









    share|improve this question
























      2












      2








      2








      I have the following list of list:



      [[Timestamp('2018-04-07 00:00:00'), Timestamp('2018-07-07 00:00:00'),Timestamp('2020-04-07 00:00:00')], [Timestamp('2018-04-07 00:00:00'),Timestamp('2018-10-07 00:00:00'),Timestamp('2018-12-07 00:00:00'),Timestamp('2021-04-07 00:00:00'),Timestamp('2022-04-07 00:00:00'),Timestamp('2023-04-07 00:00:00')]


      And my question is if it is possible filter the list of lists by another date. For example:
      If I choose this date:



      datetime.datetime(2019, 1, 26, 0, 0)


      Is there a way to filter the list of lists to just taking those dates that are higher than the date I choose and also the last one before my date?
      For example for the first list of the lists I want to keep the values:



      [Timestamp('2018-07-07 00:00:00'),Timestamp('2020-04-07 00:00:00')]


      And for the second list of the list of lists:



      [Timestamp('2018-12-07 00:00:00'),Timestamp('2021-04-07 00:00:00'),Timestamp('2022-04-07 00:00:00'),Timestamp('2023-04-07 00:00:00')] 









      share|improve this question














      I have the following list of list:



      [[Timestamp('2018-04-07 00:00:00'), Timestamp('2018-07-07 00:00:00'),Timestamp('2020-04-07 00:00:00')], [Timestamp('2018-04-07 00:00:00'),Timestamp('2018-10-07 00:00:00'),Timestamp('2018-12-07 00:00:00'),Timestamp('2021-04-07 00:00:00'),Timestamp('2022-04-07 00:00:00'),Timestamp('2023-04-07 00:00:00')]


      And my question is if it is possible filter the list of lists by another date. For example:
      If I choose this date:



      datetime.datetime(2019, 1, 26, 0, 0)


      Is there a way to filter the list of lists to just taking those dates that are higher than the date I choose and also the last one before my date?
      For example for the first list of the lists I want to keep the values:



      [Timestamp('2018-07-07 00:00:00'),Timestamp('2020-04-07 00:00:00')]


      And for the second list of the list of lists:



      [Timestamp('2018-12-07 00:00:00'),Timestamp('2021-04-07 00:00:00'),Timestamp('2022-04-07 00:00:00'),Timestamp('2023-04-07 00:00:00')] 






      python python-3.x datetime timestamp filtering






      share|improve this question













      share|improve this question











      share|improve this question




      share|improve this question










      asked Nov 15 '18 at 11:40









      AmartinAmartin

      569




      569






















          1 Answer
          1






          active

          oldest

          votes


















          1














          Something like this?



          import datetime
          from pandas import Timestamp


          # List of Timestamps
          list_of_dates = [[Timestamp('2018-04-07 00:00:00'), Timestamp('2018-07-07 00:00:00'), Timestamp('2020-04-07 00:00:00')], [Timestamp('2018-04-07 00:00:00'), Timestamp('2018-10-07 00:00:00'), Timestamp('2018-12-07 00:00:00'), Timestamp('2021-04-07 00:00:00'), Timestamp('2022-04-07 00:00:00'), Timestamp('2023-04-07 00:00:00')]]

          # Target date that we use as filter
          target_date = datetime.datetime(2019, 1, 26, 0, 0)

          def filter_dates(date_list, target_date):
          """Filter given timestamps according to target date.

          Keep last date before target date and all future dates after target date."""

          # Initialise return list
          filtered_dates =

          # Iterate over list of lists
          for dates in date_list:

          # Use list comprehension to filter dates that are on either sides of the target date
          dates_before_target_date = [date for date in dates if date < target_date]
          dates_after_target_date = [date for date in dates if date > target_date]

          # Keep last date before the target date and all future dates
          filtered_dates.append([dates_before_target_date[-1]] + dates_after_target_date)

          return filtered_dates

          filtered_dates = filter_dates(list_of_dates, target_date)
          print(filtered_dates)


          This produces



          [
          [Timestamp('2018-07-07 00:00:00'), Timestamp('2020-04-07 00:00:00')],
          [Timestamp('2018-12-07 00:00:00'), Timestamp('2021-04-07 00:00:00'), Timestamp('2022-04-07 00:00:00'), Timestamp('2023-04-07 00:00:00')]
          ]





          share|improve this answer























          • Yes it works. Thank you so much

            – Amartin
            Nov 15 '18 at 13:52










          Your Answer






          StackExchange.ifUsing("editor", function ()
          StackExchange.using("externalEditor", function ()
          StackExchange.using("snippets", function ()
          StackExchange.snippets.init();
          );
          );
          , "code-snippets");

          StackExchange.ready(function()
          var channelOptions =
          tags: "".split(" "),
          id: "1"
          ;
          initTagRenderer("".split(" "), "".split(" "), channelOptions);

          StackExchange.using("externalEditor", function()
          // Have to fire editor after snippets, if snippets enabled
          if (StackExchange.settings.snippets.snippetsEnabled)
          StackExchange.using("snippets", function()
          createEditor();
          );

          else
          createEditor();

          );

          function createEditor()
          StackExchange.prepareEditor(
          heartbeatType: 'answer',
          autoActivateHeartbeat: false,
          convertImagesToLinks: true,
          noModals: true,
          showLowRepImageUploadWarning: true,
          reputationToPostImages: 10,
          bindNavPrevention: true,
          postfix: "",
          imageUploader:
          brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
          contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
          allowUrls: true
          ,
          onDemand: true,
          discardSelector: ".discard-answer"
          ,immediatelyShowMarkdownHelp:true
          );



          );













          draft saved

          draft discarded


















          StackExchange.ready(
          function ()
          StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53318697%2ffiltering-a-list-of-lists-of-dates-in-python%23new-answer', 'question_page');

          );

          Post as a guest















          Required, but never shown

























          1 Answer
          1






          active

          oldest

          votes








          1 Answer
          1






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes









          1














          Something like this?



          import datetime
          from pandas import Timestamp


          # List of Timestamps
          list_of_dates = [[Timestamp('2018-04-07 00:00:00'), Timestamp('2018-07-07 00:00:00'), Timestamp('2020-04-07 00:00:00')], [Timestamp('2018-04-07 00:00:00'), Timestamp('2018-10-07 00:00:00'), Timestamp('2018-12-07 00:00:00'), Timestamp('2021-04-07 00:00:00'), Timestamp('2022-04-07 00:00:00'), Timestamp('2023-04-07 00:00:00')]]

          # Target date that we use as filter
          target_date = datetime.datetime(2019, 1, 26, 0, 0)

          def filter_dates(date_list, target_date):
          """Filter given timestamps according to target date.

          Keep last date before target date and all future dates after target date."""

          # Initialise return list
          filtered_dates =

          # Iterate over list of lists
          for dates in date_list:

          # Use list comprehension to filter dates that are on either sides of the target date
          dates_before_target_date = [date for date in dates if date < target_date]
          dates_after_target_date = [date for date in dates if date > target_date]

          # Keep last date before the target date and all future dates
          filtered_dates.append([dates_before_target_date[-1]] + dates_after_target_date)

          return filtered_dates

          filtered_dates = filter_dates(list_of_dates, target_date)
          print(filtered_dates)


          This produces



          [
          [Timestamp('2018-07-07 00:00:00'), Timestamp('2020-04-07 00:00:00')],
          [Timestamp('2018-12-07 00:00:00'), Timestamp('2021-04-07 00:00:00'), Timestamp('2022-04-07 00:00:00'), Timestamp('2023-04-07 00:00:00')]
          ]





          share|improve this answer























          • Yes it works. Thank you so much

            – Amartin
            Nov 15 '18 at 13:52















          1














          Something like this?



          import datetime
          from pandas import Timestamp


          # List of Timestamps
          list_of_dates = [[Timestamp('2018-04-07 00:00:00'), Timestamp('2018-07-07 00:00:00'), Timestamp('2020-04-07 00:00:00')], [Timestamp('2018-04-07 00:00:00'), Timestamp('2018-10-07 00:00:00'), Timestamp('2018-12-07 00:00:00'), Timestamp('2021-04-07 00:00:00'), Timestamp('2022-04-07 00:00:00'), Timestamp('2023-04-07 00:00:00')]]

          # Target date that we use as filter
          target_date = datetime.datetime(2019, 1, 26, 0, 0)

          def filter_dates(date_list, target_date):
          """Filter given timestamps according to target date.

          Keep last date before target date and all future dates after target date."""

          # Initialise return list
          filtered_dates =

          # Iterate over list of lists
          for dates in date_list:

          # Use list comprehension to filter dates that are on either sides of the target date
          dates_before_target_date = [date for date in dates if date < target_date]
          dates_after_target_date = [date for date in dates if date > target_date]

          # Keep last date before the target date and all future dates
          filtered_dates.append([dates_before_target_date[-1]] + dates_after_target_date)

          return filtered_dates

          filtered_dates = filter_dates(list_of_dates, target_date)
          print(filtered_dates)


          This produces



          [
          [Timestamp('2018-07-07 00:00:00'), Timestamp('2020-04-07 00:00:00')],
          [Timestamp('2018-12-07 00:00:00'), Timestamp('2021-04-07 00:00:00'), Timestamp('2022-04-07 00:00:00'), Timestamp('2023-04-07 00:00:00')]
          ]





          share|improve this answer























          • Yes it works. Thank you so much

            – Amartin
            Nov 15 '18 at 13:52













          1












          1








          1







          Something like this?



          import datetime
          from pandas import Timestamp


          # List of Timestamps
          list_of_dates = [[Timestamp('2018-04-07 00:00:00'), Timestamp('2018-07-07 00:00:00'), Timestamp('2020-04-07 00:00:00')], [Timestamp('2018-04-07 00:00:00'), Timestamp('2018-10-07 00:00:00'), Timestamp('2018-12-07 00:00:00'), Timestamp('2021-04-07 00:00:00'), Timestamp('2022-04-07 00:00:00'), Timestamp('2023-04-07 00:00:00')]]

          # Target date that we use as filter
          target_date = datetime.datetime(2019, 1, 26, 0, 0)

          def filter_dates(date_list, target_date):
          """Filter given timestamps according to target date.

          Keep last date before target date and all future dates after target date."""

          # Initialise return list
          filtered_dates =

          # Iterate over list of lists
          for dates in date_list:

          # Use list comprehension to filter dates that are on either sides of the target date
          dates_before_target_date = [date for date in dates if date < target_date]
          dates_after_target_date = [date for date in dates if date > target_date]

          # Keep last date before the target date and all future dates
          filtered_dates.append([dates_before_target_date[-1]] + dates_after_target_date)

          return filtered_dates

          filtered_dates = filter_dates(list_of_dates, target_date)
          print(filtered_dates)


          This produces



          [
          [Timestamp('2018-07-07 00:00:00'), Timestamp('2020-04-07 00:00:00')],
          [Timestamp('2018-12-07 00:00:00'), Timestamp('2021-04-07 00:00:00'), Timestamp('2022-04-07 00:00:00'), Timestamp('2023-04-07 00:00:00')]
          ]





          share|improve this answer













          Something like this?



          import datetime
          from pandas import Timestamp


          # List of Timestamps
          list_of_dates = [[Timestamp('2018-04-07 00:00:00'), Timestamp('2018-07-07 00:00:00'), Timestamp('2020-04-07 00:00:00')], [Timestamp('2018-04-07 00:00:00'), Timestamp('2018-10-07 00:00:00'), Timestamp('2018-12-07 00:00:00'), Timestamp('2021-04-07 00:00:00'), Timestamp('2022-04-07 00:00:00'), Timestamp('2023-04-07 00:00:00')]]

          # Target date that we use as filter
          target_date = datetime.datetime(2019, 1, 26, 0, 0)

          def filter_dates(date_list, target_date):
          """Filter given timestamps according to target date.

          Keep last date before target date and all future dates after target date."""

          # Initialise return list
          filtered_dates =

          # Iterate over list of lists
          for dates in date_list:

          # Use list comprehension to filter dates that are on either sides of the target date
          dates_before_target_date = [date for date in dates if date < target_date]
          dates_after_target_date = [date for date in dates if date > target_date]

          # Keep last date before the target date and all future dates
          filtered_dates.append([dates_before_target_date[-1]] + dates_after_target_date)

          return filtered_dates

          filtered_dates = filter_dates(list_of_dates, target_date)
          print(filtered_dates)


          This produces



          [
          [Timestamp('2018-07-07 00:00:00'), Timestamp('2020-04-07 00:00:00')],
          [Timestamp('2018-12-07 00:00:00'), Timestamp('2021-04-07 00:00:00'), Timestamp('2022-04-07 00:00:00'), Timestamp('2023-04-07 00:00:00')]
          ]






          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered Nov 15 '18 at 12:45









          TeemuTeemu

          686




          686












          • Yes it works. Thank you so much

            – Amartin
            Nov 15 '18 at 13:52

















          • Yes it works. Thank you so much

            – Amartin
            Nov 15 '18 at 13:52
















          Yes it works. Thank you so much

          – Amartin
          Nov 15 '18 at 13:52





          Yes it works. Thank you so much

          – Amartin
          Nov 15 '18 at 13:52



















          draft saved

          draft discarded
















































          Thanks for contributing an answer to Stack Overflow!


          • Please be sure to answer the question. Provide details and share your research!

          But avoid


          • Asking for help, clarification, or responding to other answers.

          • Making statements based on opinion; back them up with references or personal experience.

          To learn more, see our tips on writing great answers.




          draft saved


          draft discarded














          StackExchange.ready(
          function ()
          StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53318697%2ffiltering-a-list-of-lists-of-dates-in-python%23new-answer', 'question_page');

          );

          Post as a guest















          Required, but never shown





















































          Required, but never shown














          Required, but never shown












          Required, but never shown







          Required, but never shown

































          Required, but never shown














          Required, but never shown












          Required, but never shown







          Required, but never shown







          Popular posts from this blog

          Top Tejano songwriter Luis Silva dead of heart attack at 64

          政党

          天津地下鉄3号線