Query who looks if employee has more than 14 vacation days
I want a query that checks if a employee has more than 14 vacation days in a year. I want to make a trigger of it. It is important that this is 14 days in total. But the employee could have 4 days in one month and 10 days in another. He don't need to take the days in one go.
I have something like this (query) I'm using SQL Server
select employeeid
from time
where datediff(day, dateStart, dateEnd) >=1
and year(dateEnd) = 2018
and timecat= 'vacationdays'
group by employeeid
having count(*) >=13
I thought I could use a datediff and have this count like 13 times. But it doesn't work.
sql
add a comment |
I want a query that checks if a employee has more than 14 vacation days in a year. I want to make a trigger of it. It is important that this is 14 days in total. But the employee could have 4 days in one month and 10 days in another. He don't need to take the days in one go.
I have something like this (query) I'm using SQL Server
select employeeid
from time
where datediff(day, dateStart, dateEnd) >=1
and year(dateEnd) = 2018
and timecat= 'vacationdays'
group by employeeid
having count(*) >=13
I thought I could use a datediff and have this count like 13 times. But it doesn't work.
sql
Some sample data would really help here. Also, if you're using SQL Server, please add that tag to your question. SQL is just a language, not a specific product.
– Tim Biegeleisen
Nov 16 '18 at 10:55
add a comment |
I want a query that checks if a employee has more than 14 vacation days in a year. I want to make a trigger of it. It is important that this is 14 days in total. But the employee could have 4 days in one month and 10 days in another. He don't need to take the days in one go.
I have something like this (query) I'm using SQL Server
select employeeid
from time
where datediff(day, dateStart, dateEnd) >=1
and year(dateEnd) = 2018
and timecat= 'vacationdays'
group by employeeid
having count(*) >=13
I thought I could use a datediff and have this count like 13 times. But it doesn't work.
sql
I want a query that checks if a employee has more than 14 vacation days in a year. I want to make a trigger of it. It is important that this is 14 days in total. But the employee could have 4 days in one month and 10 days in another. He don't need to take the days in one go.
I have something like this (query) I'm using SQL Server
select employeeid
from time
where datediff(day, dateStart, dateEnd) >=1
and year(dateEnd) = 2018
and timecat= 'vacationdays'
group by employeeid
having count(*) >=13
I thought I could use a datediff and have this count like 13 times. But it doesn't work.
sql
sql
asked Nov 16 '18 at 10:53
DutchFatBoysDutchFatBoys
487
487
Some sample data would really help here. Also, if you're using SQL Server, please add that tag to your question. SQL is just a language, not a specific product.
– Tim Biegeleisen
Nov 16 '18 at 10:55
add a comment |
Some sample data would really help here. Also, if you're using SQL Server, please add that tag to your question. SQL is just a language, not a specific product.
– Tim Biegeleisen
Nov 16 '18 at 10:55
Some sample data would really help here. Also, if you're using SQL Server, please add that tag to your question. SQL is just a language, not a specific product.
– Tim Biegeleisen
Nov 16 '18 at 10:55
Some sample data would really help here. Also, if you're using SQL Server, please add that tag to your question. SQL is just a language, not a specific product.
– Tim Biegeleisen
Nov 16 '18 at 10:55
add a comment |
2 Answers
2
active
oldest
votes
You need to sum the date differences:
select employeeid, sum(datediff(day, dateStart, dateEnd) + 1) AS total
from time
where year(dateEnd) = 2018
and timecat= 'vacationdays'
group by employeeid
having SUM(datediff(day, dateStart, dateEnd) + 1) > 14
Consider the +1 in SUM because datediff returns 1 for two dates like '2018-11-16' and '2018-11-17', but if these are the dateStart and dateEnd you want the result to be 2.
There is still one problem remaining: what happens if dateStart and dateEnd are not dates of the same year!
Yes that problem I've also considered. But in my case that is not a problem. Thank you!
– DutchFatBoys
Nov 16 '18 at 11:46
add a comment |
Count(*) just counts the number of rows.
This means if have an employee with two vacations one of 10 days and one of 4 days, (i assume that) this are only two rows in rows in your table and count star returns 2.
You can you the function SUM()
select employeeid, sum( datediff(day, dateStart, dateEnd) ) as sum
from time
where datediff(day, dateStart, dateEnd) >=1
and year(dateEnd) = 2018
and timecat= 'vacationdays'
group by employeeid
having sum >=13
I don't know the structure of your table, therefore I'm not quite sure if the query is correct, but here a further helpful links.
https://www.w3schools.com/sql/sql_count_avg_sum.asp
Getting the sum of a datediff result
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
You need to sum the date differences:
select employeeid, sum(datediff(day, dateStart, dateEnd) + 1) AS total
from time
where year(dateEnd) = 2018
and timecat= 'vacationdays'
group by employeeid
having SUM(datediff(day, dateStart, dateEnd) + 1) > 14
Consider the +1 in SUM because datediff returns 1 for two dates like '2018-11-16' and '2018-11-17', but if these are the dateStart and dateEnd you want the result to be 2.
There is still one problem remaining: what happens if dateStart and dateEnd are not dates of the same year!
Yes that problem I've also considered. But in my case that is not a problem. Thank you!
– DutchFatBoys
Nov 16 '18 at 11:46
add a comment |
You need to sum the date differences:
select employeeid, sum(datediff(day, dateStart, dateEnd) + 1) AS total
from time
where year(dateEnd) = 2018
and timecat= 'vacationdays'
group by employeeid
having SUM(datediff(day, dateStart, dateEnd) + 1) > 14
Consider the +1 in SUM because datediff returns 1 for two dates like '2018-11-16' and '2018-11-17', but if these are the dateStart and dateEnd you want the result to be 2.
There is still one problem remaining: what happens if dateStart and dateEnd are not dates of the same year!
Yes that problem I've also considered. But in my case that is not a problem. Thank you!
– DutchFatBoys
Nov 16 '18 at 11:46
add a comment |
You need to sum the date differences:
select employeeid, sum(datediff(day, dateStart, dateEnd) + 1) AS total
from time
where year(dateEnd) = 2018
and timecat= 'vacationdays'
group by employeeid
having SUM(datediff(day, dateStart, dateEnd) + 1) > 14
Consider the +1 in SUM because datediff returns 1 for two dates like '2018-11-16' and '2018-11-17', but if these are the dateStart and dateEnd you want the result to be 2.
There is still one problem remaining: what happens if dateStart and dateEnd are not dates of the same year!
You need to sum the date differences:
select employeeid, sum(datediff(day, dateStart, dateEnd) + 1) AS total
from time
where year(dateEnd) = 2018
and timecat= 'vacationdays'
group by employeeid
having SUM(datediff(day, dateStart, dateEnd) + 1) > 14
Consider the +1 in SUM because datediff returns 1 for two dates like '2018-11-16' and '2018-11-17', but if these are the dateStart and dateEnd you want the result to be 2.
There is still one problem remaining: what happens if dateStart and dateEnd are not dates of the same year!
edited Nov 16 '18 at 11:12
answered Nov 16 '18 at 11:02
forpasforpas
19.5k4830
19.5k4830
Yes that problem I've also considered. But in my case that is not a problem. Thank you!
– DutchFatBoys
Nov 16 '18 at 11:46
add a comment |
Yes that problem I've also considered. But in my case that is not a problem. Thank you!
– DutchFatBoys
Nov 16 '18 at 11:46
Yes that problem I've also considered. But in my case that is not a problem. Thank you!
– DutchFatBoys
Nov 16 '18 at 11:46
Yes that problem I've also considered. But in my case that is not a problem. Thank you!
– DutchFatBoys
Nov 16 '18 at 11:46
add a comment |
Count(*) just counts the number of rows.
This means if have an employee with two vacations one of 10 days and one of 4 days, (i assume that) this are only two rows in rows in your table and count star returns 2.
You can you the function SUM()
select employeeid, sum( datediff(day, dateStart, dateEnd) ) as sum
from time
where datediff(day, dateStart, dateEnd) >=1
and year(dateEnd) = 2018
and timecat= 'vacationdays'
group by employeeid
having sum >=13
I don't know the structure of your table, therefore I'm not quite sure if the query is correct, but here a further helpful links.
https://www.w3schools.com/sql/sql_count_avg_sum.asp
Getting the sum of a datediff result
add a comment |
Count(*) just counts the number of rows.
This means if have an employee with two vacations one of 10 days and one of 4 days, (i assume that) this are only two rows in rows in your table and count star returns 2.
You can you the function SUM()
select employeeid, sum( datediff(day, dateStart, dateEnd) ) as sum
from time
where datediff(day, dateStart, dateEnd) >=1
and year(dateEnd) = 2018
and timecat= 'vacationdays'
group by employeeid
having sum >=13
I don't know the structure of your table, therefore I'm not quite sure if the query is correct, but here a further helpful links.
https://www.w3schools.com/sql/sql_count_avg_sum.asp
Getting the sum of a datediff result
add a comment |
Count(*) just counts the number of rows.
This means if have an employee with two vacations one of 10 days and one of 4 days, (i assume that) this are only two rows in rows in your table and count star returns 2.
You can you the function SUM()
select employeeid, sum( datediff(day, dateStart, dateEnd) ) as sum
from time
where datediff(day, dateStart, dateEnd) >=1
and year(dateEnd) = 2018
and timecat= 'vacationdays'
group by employeeid
having sum >=13
I don't know the structure of your table, therefore I'm not quite sure if the query is correct, but here a further helpful links.
https://www.w3schools.com/sql/sql_count_avg_sum.asp
Getting the sum of a datediff result
Count(*) just counts the number of rows.
This means if have an employee with two vacations one of 10 days and one of 4 days, (i assume that) this are only two rows in rows in your table and count star returns 2.
You can you the function SUM()
select employeeid, sum( datediff(day, dateStart, dateEnd) ) as sum
from time
where datediff(day, dateStart, dateEnd) >=1
and year(dateEnd) = 2018
and timecat= 'vacationdays'
group by employeeid
having sum >=13
I don't know the structure of your table, therefore I'm not quite sure if the query is correct, but here a further helpful links.
https://www.w3schools.com/sql/sql_count_avg_sum.asp
Getting the sum of a datediff result
answered Nov 16 '18 at 11:09
hobitanshobitans
11
11
add a comment |
add a comment |
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Some sample data would really help here. Also, if you're using SQL Server, please add that tag to your question. SQL is just a language, not a specific product.
– Tim Biegeleisen
Nov 16 '18 at 10:55