Getting all combinations of elements in a list (Prolog)










0















I'm trying to practice with list in Prolog.
In fact what I try to do is:
Get all combinations of elements in a list,
determine if the resulting list is longer than the input list. Here is the code:



%

descartes(,,false).

descartes(X,Result,IsExist):-
i_think(X,Result),
i_exists(X,Result,IsExist).

%should concatenate all combinations of input list
i_think(,NULL).

i_think([X|Xs],S):-
Y = Xs,
Y1 = X,
concatenate([X,Y1],Z1),
i_think(Y,T),
i_think(Xs,U),
S = [Z1,T,U].

%
concatenate([X,Y],R):-
atomics_to_string([X,Y],T),
atomics_to_string([Y,X],U),
R= [T,U].
%
i_exists(X,Y,false):-
len(X,Y,2);
len(X,Y,1).
i_exists(X,Y,true):-
len(X,Y,0).
%
len(X,Y,Count) :-
length(X,K),

length(Y,I),
(
(
K < I,
Count is 0
);
(
I < K,
Count is 2
);
(
I = K,
Count is 1
)
).


The main problem is with i_think/2, thanks for any help.
....
Specify I/O, of course, and thanks for replying:



descartes/3 : 
descartes(['gold','bank'],Result,isExist)
Result=['goldgold','goldbank','bankbank','bankgold']
isExist= true
(In fact I would prefer to erase repetitions as...)
descartes(['gold','gold'],Result,isExist)
Result=['goldgold','goldgold','goldgold','goldgold']
(this shouldn't be generated as i_exist would return true)
isExist= false









share|improve this question
























  • I ran this and found ?- descartes([a,b],L,R). L = [["aa", "aa"], [["bb", "bb"], _6960, _6966], [["bb", "bb"], _7038, _7044]], R = true ;. Can you give us a few sample input and expected output so we know what is suppose to happen. I ran your code and while I do see some combinations being generated, I see lots of extra undefined variables being created and have no idea what they are for. When you give the examples please do them for all of the predicates you created, descartes/2,i_think/2,i_exists/3

    – Guy Coder
    Nov 16 '18 at 10:47












  • FYI, NULL is a variable since it begins with a capital letter.

    – lurker
    Nov 16 '18 at 14:36















0















I'm trying to practice with list in Prolog.
In fact what I try to do is:
Get all combinations of elements in a list,
determine if the resulting list is longer than the input list. Here is the code:



%

descartes(,,false).

descartes(X,Result,IsExist):-
i_think(X,Result),
i_exists(X,Result,IsExist).

%should concatenate all combinations of input list
i_think(,NULL).

i_think([X|Xs],S):-
Y = Xs,
Y1 = X,
concatenate([X,Y1],Z1),
i_think(Y,T),
i_think(Xs,U),
S = [Z1,T,U].

%
concatenate([X,Y],R):-
atomics_to_string([X,Y],T),
atomics_to_string([Y,X],U),
R= [T,U].
%
i_exists(X,Y,false):-
len(X,Y,2);
len(X,Y,1).
i_exists(X,Y,true):-
len(X,Y,0).
%
len(X,Y,Count) :-
length(X,K),

length(Y,I),
(
(
K < I,
Count is 0
);
(
I < K,
Count is 2
);
(
I = K,
Count is 1
)
).


The main problem is with i_think/2, thanks for any help.
....
Specify I/O, of course, and thanks for replying:



descartes/3 : 
descartes(['gold','bank'],Result,isExist)
Result=['goldgold','goldbank','bankbank','bankgold']
isExist= true
(In fact I would prefer to erase repetitions as...)
descartes(['gold','gold'],Result,isExist)
Result=['goldgold','goldgold','goldgold','goldgold']
(this shouldn't be generated as i_exist would return true)
isExist= false









share|improve this question
























  • I ran this and found ?- descartes([a,b],L,R). L = [["aa", "aa"], [["bb", "bb"], _6960, _6966], [["bb", "bb"], _7038, _7044]], R = true ;. Can you give us a few sample input and expected output so we know what is suppose to happen. I ran your code and while I do see some combinations being generated, I see lots of extra undefined variables being created and have no idea what they are for. When you give the examples please do them for all of the predicates you created, descartes/2,i_think/2,i_exists/3

    – Guy Coder
    Nov 16 '18 at 10:47












  • FYI, NULL is a variable since it begins with a capital letter.

    – lurker
    Nov 16 '18 at 14:36













0












0








0








I'm trying to practice with list in Prolog.
In fact what I try to do is:
Get all combinations of elements in a list,
determine if the resulting list is longer than the input list. Here is the code:



%

descartes(,,false).

descartes(X,Result,IsExist):-
i_think(X,Result),
i_exists(X,Result,IsExist).

%should concatenate all combinations of input list
i_think(,NULL).

i_think([X|Xs],S):-
Y = Xs,
Y1 = X,
concatenate([X,Y1],Z1),
i_think(Y,T),
i_think(Xs,U),
S = [Z1,T,U].

%
concatenate([X,Y],R):-
atomics_to_string([X,Y],T),
atomics_to_string([Y,X],U),
R= [T,U].
%
i_exists(X,Y,false):-
len(X,Y,2);
len(X,Y,1).
i_exists(X,Y,true):-
len(X,Y,0).
%
len(X,Y,Count) :-
length(X,K),

length(Y,I),
(
(
K < I,
Count is 0
);
(
I < K,
Count is 2
);
(
I = K,
Count is 1
)
).


The main problem is with i_think/2, thanks for any help.
....
Specify I/O, of course, and thanks for replying:



descartes/3 : 
descartes(['gold','bank'],Result,isExist)
Result=['goldgold','goldbank','bankbank','bankgold']
isExist= true
(In fact I would prefer to erase repetitions as...)
descartes(['gold','gold'],Result,isExist)
Result=['goldgold','goldgold','goldgold','goldgold']
(this shouldn't be generated as i_exist would return true)
isExist= false









share|improve this question
















I'm trying to practice with list in Prolog.
In fact what I try to do is:
Get all combinations of elements in a list,
determine if the resulting list is longer than the input list. Here is the code:



%

descartes(,,false).

descartes(X,Result,IsExist):-
i_think(X,Result),
i_exists(X,Result,IsExist).

%should concatenate all combinations of input list
i_think(,NULL).

i_think([X|Xs],S):-
Y = Xs,
Y1 = X,
concatenate([X,Y1],Z1),
i_think(Y,T),
i_think(Xs,U),
S = [Z1,T,U].

%
concatenate([X,Y],R):-
atomics_to_string([X,Y],T),
atomics_to_string([Y,X],U),
R= [T,U].
%
i_exists(X,Y,false):-
len(X,Y,2);
len(X,Y,1).
i_exists(X,Y,true):-
len(X,Y,0).
%
len(X,Y,Count) :-
length(X,K),

length(Y,I),
(
(
K < I,
Count is 0
);
(
I < K,
Count is 2
);
(
I = K,
Count is 1
)
).


The main problem is with i_think/2, thanks for any help.
....
Specify I/O, of course, and thanks for replying:



descartes/3 : 
descartes(['gold','bank'],Result,isExist)
Result=['goldgold','goldbank','bankbank','bankgold']
isExist= true
(In fact I would prefer to erase repetitions as...)
descartes(['gold','gold'],Result,isExist)
Result=['goldgold','goldgold','goldgold','goldgold']
(this shouldn't be generated as i_exist would return true)
isExist= false






prolog






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 16 '18 at 13:04







davidza5

















asked Nov 16 '18 at 3:19









davidza5davidza5

64




64












  • I ran this and found ?- descartes([a,b],L,R). L = [["aa", "aa"], [["bb", "bb"], _6960, _6966], [["bb", "bb"], _7038, _7044]], R = true ;. Can you give us a few sample input and expected output so we know what is suppose to happen. I ran your code and while I do see some combinations being generated, I see lots of extra undefined variables being created and have no idea what they are for. When you give the examples please do them for all of the predicates you created, descartes/2,i_think/2,i_exists/3

    – Guy Coder
    Nov 16 '18 at 10:47












  • FYI, NULL is a variable since it begins with a capital letter.

    – lurker
    Nov 16 '18 at 14:36

















  • I ran this and found ?- descartes([a,b],L,R). L = [["aa", "aa"], [["bb", "bb"], _6960, _6966], [["bb", "bb"], _7038, _7044]], R = true ;. Can you give us a few sample input and expected output so we know what is suppose to happen. I ran your code and while I do see some combinations being generated, I see lots of extra undefined variables being created and have no idea what they are for. When you give the examples please do them for all of the predicates you created, descartes/2,i_think/2,i_exists/3

    – Guy Coder
    Nov 16 '18 at 10:47












  • FYI, NULL is a variable since it begins with a capital letter.

    – lurker
    Nov 16 '18 at 14:36
















I ran this and found ?- descartes([a,b],L,R). L = [["aa", "aa"], [["bb", "bb"], _6960, _6966], [["bb", "bb"], _7038, _7044]], R = true ;. Can you give us a few sample input and expected output so we know what is suppose to happen. I ran your code and while I do see some combinations being generated, I see lots of extra undefined variables being created and have no idea what they are for. When you give the examples please do them for all of the predicates you created, descartes/2,i_think/2,i_exists/3

– Guy Coder
Nov 16 '18 at 10:47






I ran this and found ?- descartes([a,b],L,R). L = [["aa", "aa"], [["bb", "bb"], _6960, _6966], [["bb", "bb"], _7038, _7044]], R = true ;. Can you give us a few sample input and expected output so we know what is suppose to happen. I ran your code and while I do see some combinations being generated, I see lots of extra undefined variables being created and have no idea what they are for. When you give the examples please do them for all of the predicates you created, descartes/2,i_think/2,i_exists/3

– Guy Coder
Nov 16 '18 at 10:47














FYI, NULL is a variable since it begins with a capital letter.

– lurker
Nov 16 '18 at 14:36





FYI, NULL is a variable since it begins with a capital letter.

– lurker
Nov 16 '18 at 14:36












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